All categories

3 years ago

1. Harold works at a men’s clothing store, which marks up its retail clothing by 27%. The

Mathematics

2 answers:

stich3 [128]3 years ago

7 0

Step-by-step explanation:

jsksbxksukwnemddkndc

Elanso [62]3 years ago

4 0

Answer:

1.783.59

2.the answer is neither $96 or $0.96. The answer is whether or not she broke even. You are not given an original purchase price so you can make one up to find the answer. I used $100, which gives a sales price of $96. The other user used $1, which gave a sales price of $0.96. Either works because they both give you the same answer that she lost money instead of breaking even.

Step-by-step explanation:

You might be interested in

If Randy sells 8 times as many vacuum cleaners as Janice, and Janice sells 690 vacuum cleaners per year, on average, how many do

drek231 [11]

Randy sells, in average, 460 vacuum cleaners per month.

<h3>How many vacuum cleaners does Randy sell each month?.</h3>

First, we know that Janice sells 690 units per year.

There are 12 months in a year, so the amount that she sells, in average, per month is:

J = 690/12 = 57.5

This means that Janice sells, in average, 57.5 units per month. And Randy sells 8 times as many, then we can solve the product:

R = 8*57.5 = 460

This means that Randy sells 460 units per month.

If you want to learn more about products:

brainly.com/question/10873737

#SPJ2

7 0

2 years ago

Bill Gates wrote a computer program that generates three random numbers

Allushta [10]

Answer:

1/1000

Step-by-step explanation:

The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:

$p(AB)=p(A)\cdot p(B)$ (1)

In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.

The total number of possible outcomes is

n = 10

While the number of succesfull outcomes (getting a 3) is only one:

$s=1$

So, the probability of drawing a 3 in 1 draw is

$p(3)=\frac{s}{n}=\frac{1}{10}$

Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get:

$p(333)=p(3)p(3)p(3)=(\frac{1}{10})(\frac{1}{10})(\frac{1}{10})=\frac{1}{1000}$

7 0

3 years ago

Help please I don’t understand

soldi70 [24.7K]

It’s A but i look good

6 0

3 years ago

Read 2 more answers

find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be

olasank [31]

Hello,

$u_{1} =4\\
 u_{2} =4*q\\
 u_{3} =4*q^2\\
...\\

 u_{9} =4*q^8\\\\
==\textgreater\ 4*q^8=1024\\
==\textgreater\ q^8=256\\
==\textgreater\ q=2\mbox{( and there is a problem in the question) } \ or \ q=-2\\
if\ q=2 \ then\ \sum_{i=0}^{8}\ 4*(2)^i= 4*\dfrac{1-2^9}{1-2} =2044\\

if \ q=-2 \ then\ \sum_{i=0}^{8}\ 4*(-2)^i= 4*\dfrac{1-(-2)^9}{1+2} =684\\



$

Answer B (but see the problem)

7 0

3 years ago

Read 2 more answers

The population of knoxville is 500,000 and is increasing

Fed [463]

Answer:

Wow :o

Step-by-step explanation:

6 0

3 years ago