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Kisachek [45]
2 years ago
10

Please Help! In which of the following intervals does the trigonometric inequality sec(x)

Mathematics
1 answer:
vovikov84 [41]2 years ago
7 0

Since this is multiple choice, we can pick any x from the listed intervals and check whether sec(x) < cot(x) is true.

• From 0 < x < π/2, take x = π/4. Then

sec(π/4) = 1/cos(π/4) = √2

cot(π/4) = 1/tan(π/4) = 1

but √2 < 1 is not true.

• From π/2 < x < π, take x = 3π/4. Then

sec(3π/4) = 1/cos(3π/4) = -√2

cot(3π/4) = 1/tan(3π/4) = -1

and -√2 < -1 is true. So sec(x) < cot(x) is always true for π/2 < x < π.

• From π < x < 3π/2, take x = 5π/4. Then

sec(5π/4) = 1/cos(5π/4) = -√2

cot(5π/4) = 1/tan(5π/4) = 1

and -√2 < 1 is true. So sec(x) < cot(x) is also true for π < x < 3π/2.

• From 3π/2 < x < 2π, take x = 7π/4. Then

sec(7π/4) = 1/cos(7π/4) = √2

cot(7π/4) = 1/tan(7π/4) = -1

but √2 < -1 is not true.

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6x+24

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After being rearranged and simplified, which of the following equations could be solved using the quadratic formula? Check all t
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The options 2x² + x² + x = 30 and  9x + 3x² = 14 + x + 1, and -x² + 4x + 7 = - x² - 9

Step-by-step explanation:

After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?

The answers are:

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3 years ago
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Step-by-step explanation:

Notice that

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Please help me with this please answer this correctly
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30 and 13


x-y=17 and x+y=43

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so y=13

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