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Aliun [14]
3 years ago
14

How many solutions does 33x+99=33x-99 have

Mathematics
2 answers:
Georgia [21]3 years ago
5 0

Answer:

0

Step-by-step explanation:

33x + 99 = 33x - 99

→ Minus 99 from both sides

33x = 33x - 198

→ Minus 33x from both sides

0x = 198

FrozenT [24]3 years ago
3 0

Answer:

No real solutions

Step-by-step explanation:

If you rearrange the equation:

33x - 33x = -99 - 99

0x = -198

Anything divided by zero is undefined/no real solution

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Plzzzzzzz give me notes of dna replication​
miskamm [114]
- A DNA strand can act as a template for synthesis of a new nucleic acid strand in which each base forms a hydrogen-bonded pair with one on the template strand (G with C, A with T, or A with U for RNA molecules). The new sequence is thus complementary to the template strand. The copying of DNA molecules to produce more DNA is known as DNA Replication.

-DNA replication takes place at a Y-shaped structure called a replication fork. A self-correcting DNA polymerase enzyme catalyzes nucleotide polymerization in a 5ʹ-to-3ʹ direction, copying a DNA template strand with remarkable fidelity. Since the two strands of a DNA double helix are antiparallel, this 5ʹ-to-3ʹ DNA synthesis can take place continuously on only one of the strands at a replication fork (the leading strand).

-On the lagging strand, short DNA fragments must be made by a “backstitching” process. Because the self-correcting DNA polymerase cannot start a new chain, these lagging-strand DNA fragments are primed by short RNA primer molecules that are subsequently erased and replaced with DNA.

-DNA replication requires the cooperation of many proteins. These include:

*DNA polymerase and DNA primase to catalyze nucleoside triphosphate polymerization;
*DNA helicases and single-strand DNA-binding (SSB) proteins to help in opening up the DNA helix so that it can be copied;
*DNA ligase and an enzyme that degrades *RNA primers to seal together the discontinuously synthesized laggingstrand DNA fragments;
*DNA topoisomerases to help to relieve helical winding and DNA tangling problems. *Many of these proteins associate with each
other at a replication fork to form a highly efficient “replication machine,” through which the activities and spatial movements of the individual components are coordinated.

Major steps involved in DNA replication are as follows:

*Each strand in a parental duplex DNA acts as a template for synthesis of a daughter strand and remains basepaired to the new strand, forming a daughter duplex (semiconservative mechanism).
*New strands are formed in the 5′ to 3′ direction.
*Replication begins at a sequence called an origin.
*Each eukaryotic chromosomal DNA molecule contains multiple replication origins.
*DNA polymerases, unlike RNA polymerases, cannot unwind the strands of duplex DNA and cannot initiate synthesis of new strands complementary to the template strands.
*Helicases use energy from ATP hydrolysis to separate the parental (template) DNA strands.
*Primase synthesizes a short RNA primer, which remains base-paired to the template DNA.
*This initially is extended at the 3′ end by DNA polymerase α (Pol α), resulting in a short (5′ )RNA- (3′)DNA daughter strand.
*Most of the DNA in eukaryotic cells is synthesized by Pol ẟ, which takes over from Pol α and continues elongation of the daughter strand in the 5′ to 3’direction.
*Pol ẟ remains stably associated with the template by binding to Rfc protein, which in turn binds to PCNA, a trimeric protein that
encircles the daughter duplex DNA.
*DNA replication generally occurs by a bidirectional mechanism in which two replication forks form at an origin and move in opposite directions, with both template strands being copied at each fork.
*Synthesis of eukaryotic DNA in vivo is regulated by controlling the activity of the MCM helicases that initiate DNA replication at multiple origins spaced along chromosomal DNA.
*At a replication fork, one daughter strand (the leading strand) is elongated continuously.
*The other daughter strand (the lagging strand) is formed as a series of discontinuous Okazaki fragments from primers synthesized every few hundred nucleotides.
*The ribonucleotides at the 5′ end of each Okazaki fragment are removed and replaced by elongation of the 3′ end of the next Okazaki fragment.
*Finally, adjacent Okazaki fragments are joined by DNA ligase.
4 0
3 years ago
-8d – 5d + 70 = 72<br> d= im so confused pls i need this
faltersainse [42]

-8d – 5d + 70 = 72

-13d + 70 = 72

        -70    -70

_______________

-13d      2

___ =  ___

-13       -13

d = -0.15 (<em>rounded</em>)

3 0
2 years ago
Reggie Turner worked 4.5 hours on Monday, from 9:45 am to 3:30 pm on Wednesday, and from
Mazyrski [523]

Answer:

Around 14 hours.

Step-by-step explanation:

Just add up all the hours.

5 0
3 years ago
How does this polynomial identity work on numerical relationships?<br> (y + x) (ax + b)
allsm [11]

Answer:

Let us take 'a' in the place of 'y' so the equation becomes

(y+x) (ax+b)

Step-by-step explanation:

Step 1:

(a + x) (ax + b)

Step 2: Proof

Checking polynomial identity.

(ax+b )(x+a) = FOIL

(ax+b)(x+a)

ax^2+a^2x is the First Term in the FOIL

ax^2 + a^2x + bx + ab

(ax+b)(x+a)+bx+ab is the Second Term in the FOIL

Add both expressions together from First and Second Term  

= ax^2 + a^2x + bx + ab

Step 3: Proof

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

Identity is Found .

Trying with numbers now

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)

((10)+8)(7) =(2*25)+(4*5)+(40)+(16)

(18)(7) =(50)+(20)+(56)

126 =126

7 0
3 years ago
Please Help With This Problem
Korolek [52]
It is B) 45 square units hope it helps
8 0
2 years ago
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