The diagram shows that FG = IJ are congruent segments due to the double tickmarks. These are the hypotenuses of the right triangles.
So that takes care of the "H" in "HL".
The L stands for "leg", so we need to have a congruent pair of corresponding legs.
Due to the orientation of the triangles, it's not clear how the corresponding legs match up, but if any of the following is true
- EF = IK
- EF = JK
- EG = IK
- EG = JK
then we'd have enough to use HL.
Answer:
−38
First do 10-16 which is -6
(7)(−6)+8/2
=−42+8/2
8/2 equals 4 so add -42 to 4
=−42+4
=−38
Answer:
This question is only if 25 points. And you have typed 50 points.
Answer is 16-4-2-1
Answer:
we can draw the graph of cosine with amplitude 2.
Step-by-step explanation:
In the given function g(x) = 2cosx we know the following parameters which are helpful to draw the graph.
Its a cosine graph given in the form of y = acos(Bx + c) + d
Here a is amplitude, period = , c = phase shift, d = vertical shift
We know a = 2, B = , c = 0, d = 0.
