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Irina18 [472]
2 years ago
12

Plz help me with this and with an explanation and I’ll give brainliest

Mathematics
1 answer:
ruslelena [56]2 years ago
4 0

Answer: Your answer would be -8

Step-by-step explanation:

You have to divide each side by factors that doesn't contain the variable.

Hope this helped you! <3

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Complete #2 for me and show proof , will give brainliest to whose right .​
Stells [14]

Answer:

<u>X</u> <u>Y</u> <u>(</u><u>X,</u><u>Y)</u>

-4 14. (-4,14)

-3 12. (-3,12)

-2 10. (-2,10)

-1 8. (-1,8)

0 6 (0,6)

1 4. (1,4)

2 2. (2,2)

4 0
2 years ago
A rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s = 120t - 4t2 meters in t seco
12345 [234]

Answer:

Step-by-step explanation:

Given that a rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s(t) = 120t - 4t^2

where t is expressed in seconds

The rock goes upto a height where the velocity becomes 0 and then it starts falling down by gravity

Velocity at time t = s'(t) = 120-8t

This becomes 0 when t =15 seconds

Hence at 15th second the rock starts falling and upto

s(15) = 120(15)-4(15^2)\\= 900 metres high it goes

The time taken to reach highest point is = 15 seconds.

6 0
3 years ago
The Florida Panther can run at a rate of 35 miles per hour. How many miles can the panther run in 3 hours?
Rainbow [258]

Answer:

105 miles in 3 hours

Step-by-step explanation:

Your Welcome

6 0
3 years ago
{4•[2+3•(6-2)+2]+2.
weqwewe [10]

Answer:

66

Step-by-step explanation:

4 0
3 years ago
What is the solution for the following equation?<br> x^2-6x+9=11
tankabanditka [31]
Make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation

if you hahve
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

1x^2-6x-2=0
a=1
b=-6
c=-2

x=\frac{-(-6)+/- \sqrt{(-6)^{2}-4(1)(-2)} }{2(1)}
x=\frac{6+/- \sqrt{36+8} }{2}
x=\frac{6+/- \sqrt{44} }{2}
x=\frac{6+/- 2\sqrt{11} }{2}
x=3+/- \sqrt{11}
x=3+ \sqrt{11} or 3- \sqrt{11}

aprox
x=6.31662 or -0.316625
4 0
3 years ago
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