Answer:
Step-by-step explanation:
1) The given inequality is



Arranging the terms with p² and p, we get

Hence, the inequality is of the form
Ap² + Bp + c < 0
2. A quadratic equation of the form
Ap² + Bp + c < 0 with A > 0 looks like
<u>Check the attached image</u>
The region where the values are negative lies between p₁ and p₂ ...
The p₁ < p < p₂
Answer:
The proof is given below.
Step-by-step explanation:
Given the two triangles which are similar we have to prove that the ratio of their angle bisectors and the side or we can say that the ratio of their altitude are proportional.
In ΔABP and ΔDEQ
∠1=∠2 (Given)
∠3=∠4 (each 90°)
By AA similarity rule ΔABP≅ΔDEQ
As if the two triangles are similar then their corresponding sides are proportional
⇒ 
Hence, Corresponding angle bisectors of similar triangles are proportional and their ratio is equal to the ratio of altitude.
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There are two ways to solve system of equations.
1) substitution method
2) elimination method
4x - y = -6
x - 2y = -5
For thus problem, i'll be using the substitute method.
So, using the equation x - 2y = -5:
Solve for "x" by adding 2y to both sides of the equation.
x = 2y - 5
Now we know what "x" is, we can substitute it in the other equation.
4x - y = -6
4(2y - 5) - y = -6
8y - 20 - y = -6
7y - 20 = -6
7y = 14
y = 2
We now know the numerical value of y. So, all we have to do is plug in y into either system of equation to solve for the numerical value of x.
4x - 2 = -6 x - 2y = -5
4x = -4 x - 2(2) = -5
x = -1 x - 4 = -5
x = -1
The solution is (-1, 2) where x equals -1 and y equals 2.