Select 4 from 9, and 3 from 8. Multiply together.
C(9,4)*C(8,3)
=9!/(4!5!) * 8!/(3!5!)
=7056
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
When naming triangles we name them by the letters on each corner so only answers with T, A, and X in them are correct, so TAX, XTA, and AXT
Answer:
All four
Step-by-step explanation:
SSS, SAS, ASA, and HL
Answer:
.08(50h) Because if the tax rate is 8%, then that is 1.08% of 50h.
Step-by-step explanation: