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Marina86 [1]
4 years ago
13

Find the value of x. DO NOT POST ANY FILES.

Mathematics
1 answer:
N76 [4]4 years ago
6 0

Answer:

9

Step-by-step explanation:

12^2+x^2=(x+6)^2

144+x^2=x^2+12x+36

12x=108

x=9

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Prove that 3^17−3^15+3^13 is divisible by 73.<br><br> HELPPPPPP PLEASEEE
Fiesta28 [93]

Answer:

Well 3^17-3^15+3^13 equals 116,385,579

Now divide that by 73

So 116,385,579 ÷ 73

That equals 1,594,323

Hope this helps

4 0
3 years ago
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Is x²-5x+3=0 is a linear equations?
Neporo4naja [7]

Answer:

No, the equation is not a linear equation.

Step-by-step explanation:

There is the x^2 thing that doesn't make it a linear equation.

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3 years ago
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[Calculus] particle at rest question. Show steps, please!
Vinvika [58]

Answer:

E

Step-by-step explanation:

We are given that a particle's position along the x-axis at time <em>t </em>is modeled by:

x(t)=2t^3-21t^2+72t-53

And we want to determine at which time(s) <em>t</em> is the particle at rest.

If the particle is at rest, this suggests that its velocity at that time is 0.

Since are we given the position function, we can differentiate it to find the velocity function.

So, by differentiating both sides with respect to <em>t</em>, we acquire:

\displaystyle x^\prime(t)=v(t)=\frac{d}{dt}\big[2t^3-21t^2+72t-53\big]

Differentiate. So, our velocity function is:

v(t)=6t^2-42t+72

So, we will set the velocity to 0 and solve for <em>t</em>. Hence:

0=6t^2-42t+72

We can divide both sides by 6:

0=t^2-7t+12

Factoring yields:

(t-3)(t-4)=0

By the Zero Product Property:

t-3\text{ and } t-4=0

Hence:

t=3\text{ and } t=4

Therefore, at the 3rd and 4th seconds, the velocity of the particle is 0, impling that the particle is at rest.

Our answer is E.

6 0
3 years ago
What is the perimeter of the trapezoid shown?
DaniilM [7]
I’m pretty sure the perimeter would be 9?
5 0
3 years ago
What's 1+1<br><br><br><br> .........
Luba_88 [7]

Answer:

1+1= 2.

Step-by-step explanation:

Have a good day!

5 0
3 years ago
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