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Marina86 [1]
3 years ago
13

Find the value of x. DO NOT POST ANY FILES.

Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

9

Step-by-step explanation:

12^2+x^2=(x+6)^2

144+x^2=x^2+12x+36

12x=108

x=9

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Juan received a bank account statement reporting the recent changes
Flura [38]

Answer:

2628.15

Step-by-step explanation:

1909.15+ 1437.99/2=2628.15

3 0
3 years ago
The difference of two numbers is 120 and thier product is 3600 find them?
maksim [4K]

Answer:

(144.8100,24.8128) (x,y)

7 0
3 years ago
What's y=-4+15 in standard form
kotykmax [81]

Answer:

y=1.1×10¹

Step-by-step explanation:

y=-4+15

y=11

y=1.1×10¹

5 0
3 years ago
(ED. 21) Analytic Geometry Unit Test..... #3 Which point is a solution of x2 + y2 > 49 and y ≤ –x2 – 4?
sdas [7]

Answer:

We want to find a solution of the system:

x^2 + y^2 > 49

y ≤ –x^2 – 4

Here we do not have any options, so let's try to find a general solution.

First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:

(x - a)^2 + (y - b)^2 = R^2

If we look at our first inequality, we can write it as:

x^2 + y^2 > 7^2

So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.

From the other equation, we would get:

y ≤ –x^2 – 4

This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.

Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.

You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:

by looking at the graph, we can see a lot of points that are solutions, like:

(0, -10)

(0, -15)

(2, -10)

etc.

8 0
3 years ago
A furniture designer builds a trapezoidal desk with a semicircular cutout. What is the area of the desk?
nirvana33 [79]

Answer:

Area = 26478cm^2

Step-by-step explanation:

Given

See attachment for desk

Required

The area

First, calculate the area of the semicircular cutout

Area = \frac{\pi r^2}{2}

Where

r = 60cm

So:

A_1 = \frac{3.14 * 60^2}{2}

A_1 = \frac{11304}{2}

A_1 = 5652cm^2

Next, the area of the complete trapezium

Area= \frac{1}{2}(a + b) * h

Where

a = 300

b = 2 * r = 2 * 60 = 120

h = 153

So:

A_2 = \frac{1}{2} * (300 + 120) * 153

A_2 = \frac{1}{2} * 420 * 153

A_2 = 32130cm^2

The area of the desk is:

Area = A_2 - A_1

Area = 32130cm^2 - 5652cm^2

Area = 26478cm^2

8 0
3 years ago
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