26 inches. Technically, since this is a perimeter problem, you need to add each length to itself and then the others. If this is confusing, you essentially need to do 5+5+8+8=26 because you have two of the fives and two eights. Perimeter is much easier than area, I promise you that
Answer:
Answer is none of these
Step-by-step explanation:
ask questions with correct options.
anyway don't repeate the mistakes again.
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
In any rhombus, the four sides are the same length.
Because of this, we know that
Furthermore, AC = AC due to the reflective property
Those three facts then allow us to prove triangle ACD is congruent to triangle ACB through the SSS congruence property. Then from CPCTC, we then know that angle DAC = angle BAC, which is enough to show that AC bisects the angle shown. The term "bisect" means "cut in half".
Answer:
A
Step-by-step explanation:
A linear term a variable to the power of one. but there is none of those so theres is no linear term. A quadratic term is a variable to the power of 2, there is one of those so our quadratic term is x^2. A constant term is a term with no variable, thats -7. Our answer is A.
Answer:
m < ANM = 36 degrees.
AM = 9.40 cm to the nearest hundredth.
Perimeter = 94.05 cm to the nearest hundredth.
Step-by-step explanation:
As we have a regular pentagon:
m < ANB = 360 / 5
= 72 degrees
So m < ANM = 1/2 * 72
= 36 degrees.
In the triangle ANM, AN = 16 so
sin 36 = Am / 16
AM = 16 sin36
= 9.4045 cm.
AB = 2 * AM = 18.809 cm
So as all sides are equal:
Perimeter = 5 * 18.809
= 94.05 cm.
