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3 years ago

9-3 divided by 4+2•12+6 divided by 2•3

Mathematics

2 answers:

olchik [2.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

9-3= 6

4+2= 8

12+6= 18

8x18= 144

144/6= 24

2*3=6

24/6= 4

Dimas [21]3 years ago

6 0

Answer:

1/34

Step-by-step explanation:

9-3= 6

(4+2x12+6)=34

6/34= 3/17 which is .1764......

3/17 divide by (2x3)= 1/34

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Half of a sphere is stacked on top of a cone. They both share a circular base. The radius of the circle is 6 millimeters. The he

Flauer [41]

Answer:

312π mm^2

Step-by-step explanation:

to find the volume of the figure, you have to calculate the volume of a cone and the volume of a sphere divided it by 2.

The volume of a cone is 1/3 * π * r ^ 2 * h, replacing the information:

V = 1/3 * (6) ^ 2 * (14) = 168π mm^2

The volume of a sphere is 4/3 * π * r ^ 3, replacing the information:

V = 4/3 * π * (6) ^ 3 = 288π mm^2

but since you only have half the sphere

V = 288π / 2 = 144π mm^2

then the total volume is

Vt = 168π + 144π = 312π mm^2

5 0

2 years ago

Read 2 more answers

Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and

pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

$104=1\times 2\times 2\times 2\times 13$

$88=1\times 2\times 2\times 2\times 11$

Form above , we can say that common factors are :

$HCF=2\times 2\times 2=8$

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0

3 years ago

Read 2 more answers

~please only answer if you know for sure~

NARA [144]

JKL is similar to PQR

so they want PR

JKL is similar to PQR

So PR is similar to JL

And they also give us the sides KL and QR

JKL is similar to PQR

Both of those sides are similar, so we can form a proportion.

$\sf { \frac{PR}{JL} = \frac{QR}{KL} }$

Plug in the numbers:

$\sf { \frac{PR}{6} = \frac{15}{9} }$

Cross multiply:

$\sf{ PR \times 9 = 6 \times 15}$

Isolate PR

$\sf{ PR = \frac{6 \times 15}{9}}$

Simplify it

$\sf{ PR = 10}$

So your final answer is

$\boxed{\bf{10 centimeters}}$