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Ronch [10]
2 years ago
14

Please help I am begging you extra points and BRAINLIEST!!!!!!!

Mathematics
1 answer:
aniked [119]2 years ago
6 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of linear equations.

Sheet - 1

1.) m = -8

2.) n = 10

3.) b = 45

4.) x = -40

5.) p = 2

6.) x = 6

7.) x = -4

8.) x = 4.5

9.) x = 8

10.) w = 40

Sheet - 2

1.) x = 2

2.) x = -2

3.) x = 20

4.) x = -3/2

5.) x = -8

6.) x = 11

7.) x = 0

8.) x = 5

9.) x = -10/3

10.) x = 30

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-x/6+0

Step-by-step explanation:

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The table represents the function f (x) = 2 x + 1.
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C

Step-by-step explanation:

In the table, we are given the points [ (-3, -5), (2, y), (5, 11), (8, 17) ]

We are given the equation [ f(x) = 2x + 1 ] where 2 = slope and 1 = y intercept.

We need to find the value of "y".

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y-(-5)/2-(-3) = 2

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3 years ago
Read 2 more answers
A sneaker company can make 50 pairs of sneakers for every 6 yards of material. Make a table to show the relation between materia
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A sneaker company can make 50 pairs of sneakers for every 6 yards of material.

Then in each case you can consider proportion.

1. 50 pairs -- 6 yards,

80 pairs -- x yards.

Mathematically,

\dfrac{50}{80}=\dfrac{6}{x},\\ \\x=\dfrac{80\cdot 6}{50}=9.6\ yards.

2. 50 pairs -- 6 yards,

100 pairs -- x yards.

Mathematically,

\dfrac{50}{100}=\dfrac{6}{x},\\ \\x=\dfrac{100\cdot 6}{50}=12\ yards.

3. 50 pairs -- 6 yards,

120 pairs -- x yards.

Mathematically,

\dfrac{50}{120}=\dfrac{6}{x},\\ \\x=\dfrac{120\cdot 6}{50}=14.4\ yards.

4. 50 pairs -- 6 yards,

140 pairs -- x yards.

Mathematically,

\dfrac{50}{140}=\dfrac{6}{x},\\ \\x=\dfrac{140\cdot 6}{50}=16.8\ yards.

Thus, the table is

\begin{array}{cc}\text{Pairs}&\text{Yards}\\50&6\\80&9.6\\100&12\\120&14.4\\140&16.8\end{array}

The domain of the relation is the set \{50,80,100,120,140\} and the range of the relation is \{6,9.6,12,14.4,16.8\}.See attached diagram for the graph of the relation.

4 0
3 years ago
Mountain View Middle School students work on square desktops. The area of the square desk surface is 4 square feet. What is the
ahrayia [7]

Answer:

2 Feet

Step-by-step explanation:

The area is found by multiplying length by width. Since its a square the length and width are the same and it would have to be 2.

8 0
2 years ago
while visiting a mountain, John approximated the angle of elevation to the top of a hill to be 25 degrees. Alfter walking 350 fe
strojnjashka [21]
There are several ways of going about this problem, but just know that it all boils down to triangles and the rules/laws of triangles.
So we start by making a large right triangle, because the hill is vertical with the horizontal ground, with 25° as the left angle (where John looks up to top), 90° is the right angle (where ground meets hill base). So we see that the top side of the triangle is the hypotenuse, and equals the line of sight from John to hilltop.
Now we've got additional information that if John walks 350ft towards the hill, his angle of elevation increases by 14. So that = 25+14 = 39. How does that possibly help us?? Well now we can make 2 triangles inside of the one we've already made. So that now we have the triangle base split between the left angle of 25° and where he stopped 350ft to the right of that.
Now the supplement of 39 is 141, and the remaining piece of that too left triangle = 180-25-141 = 14. What does that mean? Well now we have a triangle, where we know all 3 angles and 1 side --> we can find another side by the law of sines:
If a, b and c are the lengths of the legs of a triangle opposite to the angles A, B and C respectively; then the law of sines states:
a÷sinA = b÷sinB = c÷sinC
We really need the hypotenuse to then find our hill height, so we'll make hypotenuse = side b in attached image. That being so, then its opposite angle (B) = 141. And the top right angle (C) = 14 with its opposite side (c) = 350ft.
Now we only need b÷sinB = c÷sinC
So b/sin141 = 350/sin14 --> b = 350sin141/sin14 = 350×.63/
b = 220.3/.24 = 910.47 ft
Now that's our hypotenuse, so using our original large right triangle, we can use right triangular trig. to solve. Let's make the right side, our hill height, equal to x.
Sin ¥ = opp. side / hypotenuse -->
Sin ¥ = x / hypotenuse
Sin25 = x / 910.5
x = 910.5×sin25 = 910.5×.423
x = 384.8 ft

3 0
3 years ago
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