F(x) = 4(x² - 6x + ___) + 20
completing the square.
a² + 2ab + b²
a² = x² = x * x
2ab = -6x = 2*x* -3
b² = -3² = 9
f(x) = 4(x² - 6x + 9) + 20
f(x) = 4x² - 24x + 36 + 20
f(x) = 4x² - 24x + 56
Answer: 1. (p^2 - 6)(1 - q(p^2 - 6)) 2. (a - b)(z + a - b)
Step-by-step explanation:
In the first question think of p^2 - 6 as the letter A. You would get A - q A^2, factorizing it to get A(1-qA). Then substituting the A with the p^2 - 6, you would get (p^2 - 6)(1 - q(p^2 - 6))
Now in the next question, you need to understand the priniciple
(a - b) ^ 2 = (b - a) ^ 2
As a^2 - 2ab + b^2 = b^2 - 2ab + a^2
So we get z(a - b) + (a - b) ^ 2 and using the same technique from the last question, you get (a - b)(z + a - b)
Hope this helps!!!
78 = -2(m + 3) + m
78 = -2m - 6 + m
78 = -m - 6 |add 6 to both sides
84 = -m
m = -84
The constant of proportionality represents the unit cost .You use the equation y = 8.5 x to calculate the total cost y in dollars for x in what ever you are buying