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Zinaida [17]
3 years ago
10

Which ion is common to all alkalis

Chemistry
1 answer:
Pani-rosa [81]3 years ago
5 0
The ion hydroxide is common to all alkalis.
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How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL o
Rama09 [41]

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

<u>Step 1: </u>Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

<u>Step 2:</u> The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

<u>Step 3:</u> Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH =  0.0075 moles

<u>Step 4</u>: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

<u>Step 5:</u> Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

7 0
3 years ago
Which of the following statements is true about nuclear power? A) It releases greenhouse gases. B) It does not produce wastes. C
antiseptic1488 [7]

A?

I think its A but I am not 100% sure.

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3 years ago
Fill in the blank <br> ______ is a way to describe matter with numbers and units.
Viktor [21]
Measurements I’m pretty sure
4 0
3 years ago
Read 2 more answers
How many atoms in 0.026mol of Cr?​
Helga [31]
Multiply avagadro’s number to the mole
(6.022x10^22) x (0.026)=1.565 x 10^22
5 0
3 years ago
Balance the equation in acidic conditions. phases are optional. equation: cu no_{3}^{-} -&gt; cu^{2 } no cu no−3⟶cu2 no
d1i1m1o1n [39]

Cu + 2NO₃⁻  + 4H⁺ → Cu⁺² + 2NO₂ + 2H₂O this is the balanced chemical equation in acidic medium.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the given equation

Cu + NO₃⁻ → Cu⁺² + NO₂

Here we can see that all atoms other than O and H are balanced.

In the given equation oxidation number of Cu changes from 0 to +2.

In the given equation oxidation number of N changes from 5 to 4.

Now multiply by 2 with NO₃⁻ and NO₂.

Cu + 2NO₃⁻ → Cu⁺² + 2NO₂

Now ad the water molecules in right hand side to balanced the O atoms.

Cu + 2NO₃⁻  → Cu⁺² + 2NO₂ + 2H₂O

Now add 4H⁺ on the left hand side to balance the H atoms.

Cu + 2NO₃⁻  + 4H⁺ → Cu⁺² + 2NO₂ + 2H₂O

Thus from the above conclusion we can say that Cu + 2NO₃⁻  + 4H⁺ → Cu⁺² + 2NO₂ + 2H₂O this is the balanced chemical equation in acidic medium.

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

#SPJ4

8 0
2 years ago
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