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3 years ago

For the hypothetical compound AX2 which statement is true

Chemistry

2 answers:

Komok [63]3 years ago

7 0

Answer:

D. A is a metal from group 2, and X is a nonmetal from group 7

zloy xaker [14]3 years ago

4 0

Answer: Option (D) is the correct answer.

Explanation:

Metals are the species which tend to lose electrons in order to attain stability. When a metal loses one electron then it acquires a +1 charge and if a metal loses 2 electrons then it acquires a +2 charge and so on.

On the other hand, non-metals are the species which tend to gain electrons in order to attain stability.

When one electron is gained by a non-metal then it acquires a -1 charge and when two electrons are gained by a non-metal then it acquires a -2 charge and so on.

For example, a metal of group 2 will have a +2 charge in ionic form and when it combines with a non metal who needs to gain one or two electrons then the compound formed will be $AX_{2}$ .

As $MgCl_{2}$ can be assumed in place of $AX_{2}$ .

Thus, we can conclude that the statement A is a metal from group 2, and X is a nonmetal from group 7.

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What are the three states of a substance essential for life on earth

Dafna11 [192]

Liquid solid and gas

5 0

3 years ago

The Haber reaction for the manufacture of ammonia is: N2 + 3H2 → 2NH3 Without doing any experiments, which of the following can

Dimas [21]

Answer : The correct statement is, $\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

The expression for rate of reaction :

$\text{Rate of disappearance of }N_2=-\frac{d[N_2]}{dt}$

$\text{Rate of disappearance of }H_2=-\frac{1}{3}\frac{d[H_2]}{dt}$

$\text{Rate of formation of }NH_3=+\frac{1}{2}\frac{d[NH_3]}{dt}$

From this we conclude that,

$\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)$

Hence, the correct statement is, $\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)$

3 0

4 years ago

The chemical equation below shows the burning of magnesium (Mg) with oxygen (O2) to form magnesium oxide (MgO). 2Mg + O2 Right a

Nadusha1986 [10]

Answer:

64.0

Explanation:

2Mg+O2 ---> 2MgO

use dimentional analysis to find the amount of moles of O2 needed first

4.00molMg x 1.00mol O2/ 2.00 mol Mg=. 2.00 mol O2

using the coefficients you can see the mole ratio for O2:Mg the mole ratio is 1:2 which is why there is 1 mole on the top for 2 moles on the bottom. The Mg would cancel and multiply 4 by 1 then divide by 2, or multipy 4 by 1/2

Now that you have the moles of O2 you use the molar mass to find the grams in 2 moles of O2

2.00 mol O2 x 32.0g/1.00 mol = 64.0 g

multiply 2 by 32

4 0

3 years ago

What is bromin what is bromine what is bromine

yulyashka [42]

Answer:

Bromine is a chemical element with the symbol Br and atomic number 35. It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly colored gas.

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3 years ago

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Naddik [55]

Answer:

Explanation:

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3 years ago