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2 years ago

NO LINKS!!Solve each equation. Show all work.(x - 2)^2 - 64 = 0

Mathematics

2 answers:

klasskru [66]2 years ago

4 0

$(x-2)^2-64=0\\(x-2)^2=64\\x-2=8 \vee x-2=-8\\x=10 \vee x=-6$

TEA [102]2 years ago

4 0

Answer:

If you have to show the value of x then you can take either and or but when you have to equation then you can show only eqn.

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3 years ago

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3 years ago

Read 2 more answers

The sum of twice a number and 6

Allushta [10]

Answer:

The answer to your question is 4

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3 years ago

I'm so confused! what answer am i missing???

Marina86 [1]

The point P could be located in quadrant I, quadrant IV and the x-axis

<h3>How to determine the quadrant?</h3>

The coordinate of point P is given as:

P = (a, b)

Where a is positive

When a is positive, then the likely locations of P are:

On the x-axis, when b = 0
In quadrant I, when b is positive
In quadrant IV, when b is negative

Hence, point P could be located in quadrant I, quadrant IV and the x-axis

NO LINKS!!Solve each equation. Show all work.(x - 2)^2 - 64 = 0​

NO LINKS!!Solve each equation. Show all work.(x - 2)^2 - 64 = 0