Our weight on the moon is less than it would be on earth due to a different of the strength of gravity on the moon
Answer : The net ionic equation will be,

Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The given balanced ionic equation will be,

The ionic equation in separated aqueous solution will be,

In this equation,
are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,

The balanced equation for the reaction between Ba(OH)₂ and HCl is as follows;
Ba(OH)₂ + 2HCl ---> BaCl₂ + 2H₂O
stoichiometry of Ba(OH)₂ to HCl is 1:2
the number of HCl moles that have reacted - 0.2452 mol/L x (20.00 x 10⁻³ L)
number of HCl moles reacted = 0.004904 mol
2 mol of HCl reacts with 1 mol of Ba(OH)₂
therefore 0.004904 mol of HCl reacts with - 1/2 x 0.004904 mol of Ba(OH)₂
number of Ba(OH)₂ moles in 18.15 mL - 0.002452 mol
Therefore number of Ba(OH)₂ moles in 1000 mL- 0.002452 mol /(18.15 x 10⁻³ L)
molarity of Ba(OH)₂ is = 0.1351 M
Answer:
Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
Explanation:
Answer:
<u>2P (s) + 5PCl₂ (g) → 2PCl₅ (s)</u>
Explanation:
There are 2 chlorine atoms on the reactant side and 5 chlorine atoms on the product side.
Hence, multiply the left chlorine molecule by 5 and right compound by 2.
⇒ P (s) + 5 × Cl₂ (g) → 2 × PCl₅
⇒ <u>P (s) + 5Cl₂ (g) → 2PCl₅ (s)</u>
But, now we see that there is 1 phosphorus atom on the reactant side and 2 phosphorus atoms on the right.
So, multiply the left phosphorus atom by 2 to balance.
⇒ 2 × P (s) + 5PCl₂ (g) → 2PCl₅ (s)
⇒ <u>2P (s) + 5PCl₂ (g) → 2PCl₅ (s)</u>