I’m taking a test right now and I had to rush so I wasn’t able to study please help..
2 answers:
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The given equations are
(a) Solution by graphing both the equations:
Graph for both the equations (i) and (ii) are in the figure. The point of intersection of both the graph is the solution of the equations.
From the graph, the point of intersection is (4,3)).
Hence, the required solution is (4,3).
(b) Solution by elimination method:
Equations (ii) can be written as -x+y=-1, now multiply it by 2, we have
Add equations (i) and (iii), we have
2x-3y=-1
-2x+2y=-2
__________
Putting the value of y=3 in equation (i), we have
Hence, the required solution is (4,4).
(c) Solution by substitution method:
Substituting the value of y from equation (ii) to equation (i), we have
Putting the value of x=4 in equation (i), we have
.
Hence, the required solution is (4,3).
This question is not complete. Find attached the complete question and the figure showing the two way table.
Answer:
a. P(owns a cellphone) = 781/1000
b. P(does not own a PS4) = 421/500
c. P(owns a PS4 U does not own a cellphone) = 377/1000
d. P(owns a PS4 n does not own a cellphone) = 25/158
e. P(owns a PS4 | own a cell phone) =
158/1000
f. P(owns a cellphone | own a PS4) = 781/1000
Step-by-step explanation:
Total number of students = 1000 students
We have two variables,
1. The students who own cellphones
2. The students who own PS4
a. P(owns a cellphone)
From the question and the table, we are told that 781 people own cellphones.
Hence, P(owns a cellphone) = 781/1000
b. P(does not own a PS4)
From the attached table, we can see that the number of students that does not own a PS4 = 842
Hen P(does not own a PS4) = 842/1000 = 421/500
c. P(owns a PS4 U does not own a cellphone) =
First we find the Probability of student that owns a PS4
Number of students that own a PS4 = 158
P(owns a PS4 ) = 158/1000
Number of students that does not own a cell phone = 219
P(does not own a cell phone) = 219/1000
Therefore, P(owns a PS4 U does not own a cellphone) = P(owns a PS4 ) + P(does not own a cell phone)
= 158/1000 +219/1000
= 377/1000
d. P(owns a PS4 n does not own a cellphone) =
From the table, we obtain that as =
25/158
e. P(owns a PS4 | own a cell phone) =
P(owns a PS4 n own a cell phone) ÷ P(own a cell phone)
= P(owns a PS4)
From the table that would give us = 158/1000
f. P(owns a cellphone | own a PS4) =
P(owns a cellphone n own a PS4) ÷ P(own a PS4)
= P(owns a cellphone
From the table, this is given as :
781/1000
