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olga2289 [7]
3 years ago
14

How much work is needed to move an object 20 meters with 40 newtons of force?

Physics
1 answer:
Ann [662]3 years ago
3 0

Answer: c I think is the answer

Explanation:

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A small remote-control car with a mass of 1.65 kg moves at a constant speed of v = 12.0 m/s in a vertical circle inside a hollow
Reil [10]

Answer:

N=63.69N

Explanation:

The normal force exerted on the car by the walls of the cylinder at the bottom of the vertical circle will be such that when substracted to the weight it must give the centripetal force, since at that point on the vertical F_{cp}=N-W=N-mg

We also know that the equation for the centripetal force is:

F_{cp}=ma_{cp}=\frac{mv^2}{r}

Mixing both equations we get:

N-mg=\frac{mv^2}{r}

N=mg+\frac{mv^2}{r}

Which for our values means:

N=(1.65Kg)(9.8m/s^2)+\frac{(1.65Kg)(12m/s)^2}{(5m)}=63.69N

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3 years ago
The motion of a particle along a straight line is described by the equation x=6+4t2 -t 4 , where x is in meter and t is in secon
Aleks [24]

Answer:

The position of the particle is 6m

The velocity of the particle is 16 m/s in negative direction

The acceleration of the object is -40 m/s²

Explanation:

Given;

motion of the particle along a straight line as x = 6 + 4t² - t⁴

The position of the object when t = 2s

x = 6 + 4(2)² - (2)⁴

x = 6 + 16 - 16

x = 6m

The velocity of the object when t = 2s

Velocity = dx/dt

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when t = 2s

Velocity = 8(2) - 4(2)³

Velocity = 16 - 32

Velocity = -16m/s

Velocity = 16 m/s (in negative direction)

The acceleration of the object when t = 2s

Acceleration = d²x/dt² = 8 - 12t²

Acceleration = 8 - 12 (2)²

Acceleration =  -40 m/s²

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4 years ago
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0.5mv^2
0.5 times 40 times 3^2
The kinetic energy is 180
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3 years ago
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