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tensa zangetsu [6.8K]
2 years ago
7

how many helium-filled balloons would it take to lift a person? assume the person has a mass of 73 kgkg and that each helium-fil

led balloon is spherical with a diameter of 30 cm cm .
Physics
1 answer:
aliina [53]2 years ago
4 0

Answer:

Mass = volume * density

tables show air = 1.293 g / L and He = .178 g / L

Each balloon would have a lifting power (using mass) of

(1.293 - .178) = 1.115 g / L = 1.115 kg / m^3

Note there are 1000 g in a kg and 1000 L in a m^3

V (balloon) = 4/3 pi .15^3 = .0141 m^3

Each balloon can lift .0141 m^3 * 1.115 kg/m^3 = .0158 kg

Or 63.4 balloons can lift 1 kg

To lift 75 kg requires 63.4 * 75 = 4760 balloons

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The mass of the earth is 5.98 1024 kg, the mass of the moon is 7.36 1022 kg, and the distance between the centers of the earth a
Setler [38]

Answer:

 x_{cm} = 4.644 10⁶ m

Explanation:

The center of mass is given by the equation

         x_{cm} = 1 / M_{total}  ∑ x_{i}  m_{i}

Where M_{total} is the total masses of the system, x_{i} is the distance between the particles and m_{i} is the masses of each body

Let's apply this equation to our problem

        M = Me + m

        M = 5.98 10²⁴ + 7.36 10²²

        M = 605.36 10²² kg

Let's locate a reference system located in the center of the Earth

Let's calculate

       x_{cm} = 1 / 605.36 10²²   [Me 0 + 7.36 10²² 3.82 10⁸]

       x_{cm} = 4.644 10⁶ m

4 0
2 years ago
PLSSS HELP I WILL GIVE U BRAINLIEST annabelle and jose are building a complete circuit for their science inquiry in class they w
Agata [3.3K]

Answer:

i think its C hope this is rhight have a good day

Explanation:

6 0
3 years ago
Read 2 more answers
LARGER vibration produces a higher ............
balandron [24]
A or possibly C because the other options have nothing to do with the size of the vibration. If i was you I would answer with A

8 0
3 years ago
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turn
Cerrena [4.2K]

Answer:

e. Not enough information to determine

Explanation:

This question is incomplete. Here is the complete question with my solution afterwards;

A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.

What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)

a. The ladybug begins to slide

b. The gentleman bug begins to slide

c. Both bugs begin to slide at the same time

d. Nothing ever happens

e. Not enough information to determine

The centripetal force acting on a rotating body or bugs can be written as,

F=mrw^2

m= mass of the corresponding bugs

r= corresponding radial distance of each bug

w= angular speed of the turntable

The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable

F ∝ mr

Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.

Option "e" is correct.

7 0
2 years ago
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suppose the same chest is at rest. you push it horizontally with force of 110N but it does not budge. What is the contact force
Radda [10]

Answer:

110 N

Explanation:

When a force is applied on a body and body does not move, it means the body remains at rest.

In this condition, there is a contact force between the body and the floor which is called static friction.

Th static friction force is a self adjusting force and comes into play when the body is at rest.

Here, the applied force is 110 N and the chest is not moving, that means a static friction force is acting between the chest and the floor. This static friction force is the force of contact between the chest and the floor. The static friction force is equal to the applied force when the body does not move.

So, the contact force between the chest and the floor is 100 N.

4 0
3 years ago
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