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MA_775_DIABLO [31]
3 years ago
14

Solving equation for the quantity indicated

Physics
2 answers:
Slav-nsk [51]3 years ago
7 0
T = (vf -vo)/a. .......
wariber [46]3 years ago
4 0
First, multiply each side by ' t '. Then, divide each side by ' a '.
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At least how many Calories does a mountain climber need in order to climb from sea level to the top of a 5.42 km tall peak assum
Verdich [7]

Answer:

Ec = 6220.56 kcal

Explanation:

In order to calculate the amount of Calories needed by the climber, you first have to calculate the work done by the climber against the gravitational force.

You use the following formula:

W_c=Mgh        (1)

Wc: work done by the climber

g: gravitational constant = 9.8 m/s^2

M: mass of the climber = 78.4 kg

h: height reached by the climber = 5.42km = 5420 m

You replace in the equation (1):

W_c=(78.4kg)(9.8m/s^2)(5420m)=4,164,294.4\ J     (2)

Next, you use the fact that only 16.0% of the chemical energy is convert to mechanical energy. The energy calculated in the equation (2) is equivalent to the mechanical energy of the climber. Then, you have the following relation for the Calories needed:

0.16(E_c)=4,164,294.4J

Ec: Calories

You solve for Ec and convert the result to Cal:

E_c=\frac{4,164,294.4}{016}=26,026,840J*\frac{1kcal}{4184J}\\\\E_c=6220.56\ kcal

The amount of Calories needed by the climber was 6220.56 kcal

4 0
3 years ago
A belt of negligible mass passes between cylinders A and B and is pulled to the right with a force P. Cylinders A and B weigh, r
V125BC [204]

Answer:

(a) whether slipping occurs between the belt and the cylinder i think is the answer dont hate if you get it wrong please and thank you.

Explanation:

i am just guessing otay.

7 0
3 years ago
Find the voltage drop (in volt) along a 93.4 meter long 10 gauge copper wire carrying acurrent of 72.5 A. The diameter of a 10 g
Sophie [7]

Answer: 5.41 V

Explanation:in order to explain this result we have to use the Ohm law given by:

ΔV=R*I where R is the resistance which is equal R= ρ*L/A . ρ is the resistivity, L the length of the wire and A is the cross section. I is the current.

Then we have

ΔV=ρ*L*I/A= 1.68 * 10^-8 Ωm*93.4 m*72.5A/2.1* 10^-5 m^2=5.41 V

3 0
3 years ago
Help me to answer my questions please
Andrei [34K]
2 is c
3 is a 
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3 0
3 years ago
Which factors could be potential sources of error in the experiment? check all that apply.
Vadim26 [7]

(A)energy lost in the lever due to friction

(C) visual estimation of height of the beanbag

(E)position of the fulcrum for the lever affecting transfer of energy

6 0
3 years ago
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