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MA_775_DIABLO [31]
3 years ago
14

Solving equation for the quantity indicated

Physics
2 answers:
Slav-nsk [51]3 years ago
7 0
T = (vf -vo)/a. .......
wariber [46]3 years ago
4 0
First, multiply each side by ' t '. Then, divide each side by ' a '.
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Help me its physical science and i don't know what to do tyyy​
miskamm [114]

The thing to do here is to balance the eqns that is to balance the stoichometric ratios or coefficients of the cpds.

hope you understand. all the best.

7 0
3 years ago
A lamp hangs vertically from a cord in a descending elevator that decelerates at 1.7 m/s2. (a) if the tension in the cord is 63
zubka84 [21]

(a)
The formula is: 
∑ F = Weight + T = mass * acceleration 

as the elevator and lamp are moving downward, I choose downward forces to be positive. 
Weight is pulling down = +(9.8 * mass) 
Tension is pulling up, so T = -63 
Acceleration is upward = -1.7 m/s^2 

(9.8 * mass) + -63 = mass * -1.7 
Add +63 to both sides 
Add (mass * 1.7) to both sides 

(9.8 * mass) + (mass * 1.7) = 63 
11.5 * mass = 63

mass = 63 / 11.5 

Mass = 5.48 kg 


(b)
Since the elevator and lamp are going upward, I choose upward forces to be positive. 
Weight is pulling down = -(9.8 * 5.48) = -53.70 
Acceleration is upward, so acceleration = +1.7 


-53.70 + T = 5.48 * 1.7

T = 53.70 + 9.316 = approx 63 N 

The Tension is still the same - 63 N since the same mass, 5.48 kg, is being accelerated upward at the same rate of 1.7 m/s^2

3 0
3 years ago
If a car rolls gently off a vertical cliff, how long does it take to reach 90km/hr.
Naddik [55]
90 km/h : 3.6 = 25 m/s. If you know that on earth g = 9.81 m/s^2, then all you have to do is divide the speed by g. 25/9.81 = 2.548 seconds

At least, if by 'gently rolls off a vertical cliff' means that your starting velocity equals zero.
5 0
3 years ago
A 7.0 kg bowling ball has a moment of inertia of 2.8x10-2 kg m2, and a radius of 0.10 m. If it rolls down the lane at an angular
slega [8]

Hi there!

Angular momentum is equivalent to:

\large\boxed{L = I\omega}

L = angular momentum (kgm²/s)

I = moment of inertia (kgm²)

ω = angular velocity (rad/sec)

Plug in the given values for moment of inertia and angular speed:

L = (0.028)(40) = \boxed{1.12 kgm^2/s}

8 0
2 years ago
Question 18 of 25
frozen [14]
The answer would be A transverse
5 0
3 years ago
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