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Maslowich
3 years ago
11

PLEASE HELP ME QUICK DUDES!!

Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

See graph attached

Step-by-step explanation:

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Write a word that has a line symmetry like the word Ohio draw the lines of symmetry for each letter
Igoryamba
MOM and DECK can be included.
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3 years ago
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I WILL MARK BRAINLIEST!
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The answer is the third one 
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4 years ago
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2. Solve 10^6x = 93. Round to the nearest ten-thousandth. (1 point)
Anit [1.1K]
2. 0.3281
3. 1.31

2. 10^(6x) = 93
For this problem, using a calculator makes it quite simple. What you want is the power that you can raise 10 to that gives you 93. That value is the logarithm of 93 to base 10. So
10^(6x) = 93
log(10^(6x)) = log(93)
6x = 1.968482949
x = 0.328080491
x = 0.3281

3. This problem is both trickier and easier than the previous. All you need to do is plot the function on your calculator and look for the answer that's nearest which is 1.31, you could also get a more precise answer by calculating the logarithm to base 5.5 of 805. You won't find such a logarithm function on your calculator, but that isn't a major problem since you can easily convert a logarithm from any base to any other base by simply dividing by the logarithm of the desired base. So:
5.5^(3x) = 805
log(5.5^(3x)) = log(805)
log(5.5^(3x))/log(5.5) = log(805)/log(5.5)
log to base 5.5 of 5.5^(3x) = log(805)/log(5.5)
3x = 2.90579588/0.740362689
3x = 3.92482755
x = 1.30827585
x = 1.31
3 0
3 years ago
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X + y + w = b
White raven [17]

Answer:

(a) a=6 and b≠\frac{11}{4}

(b)a≠6

(c) a=6 and b=\frac{11}{4}

Step-by-step explanation:

writing equation in agumented matrix form

\begin{bmatrix}1 &1 & 0 &1 &b\\ 2 &3 & 1 &5 &6\\ 0& 0 & 1 &1 &4\\ 0& 2 & 2&a &1\end{bmatrix}

now R_{2} =R_{2}-2\times R_{1}

\begin{bmatrix}1 &1& 0 &1 &b\\ 0 &1& 1 &3 &6-2b\\ 0& 0 & 1 &1 &4\\ 0& 2 & 2&a &1\end{bmatrix}

now R_{4} =R_{4}-2\times R_{2}

\begin{bmatrix}1 &1& 0 &1 &b\\ 0 &1& 1 &3 &6-2b\\ 0& 0 & 1 &1 &4\\ 0& 0 & 0 &a-6 &4b-11\end{bmatrix}

a) now for inconsistent

rank of augamented matrix ≠ rank of matrix

for that  a=6 and b≠\frac{11}{4}

b) for consistent w/ a unique solution

rank of augamented matrix = rank of matrix

  a≠6

c) consistent w/ infinitely-many sol'ns

  rank of augamented matrix = rank of matrix < no. of variable

for that condition

 a=6 and b=[tex]\frac{11}{4}

then rank become 3 which is less than variable which is 4.

4 0
4 years ago
you have 5 mini pizzas to share with 4 friends. You're cutting the pizzas in half, how much will each friend? How can you make s
Alona [7]
I believe that they will get 1 and 1/2 of a pizza and u would have to cut the pizza in half to the point u can give all four of them the left over I hope this works I really don't know I tried
7 0
3 years ago
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