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3 years ago

15

Exactly one of the numbers 2,3 5 and 7 is placed in each of the 4 empty regions formed by circles A, B and C so that the sum of

the numbers in each circle is the same. Each number is used. What is the sum of the numbers in each circle? *

1 answer:

Schach [20]3 years ago

5 0

Answer:

The sum of the numbers in each circle is 17

Step-by-step explanation:

The numbers to choose from are:

2, 3, 5, 7

By this alone the biggest number must be in the overlap of the three circles.

Then just fill in the numbers in such a way that they all are used.

The sum of the numbers in each circle is 17.

See picture for a solution.

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

4 0

3 years ago

Help me please no links

kirza4 [7]

Answer:

the answer is 4

Step-by-step explanation:

7 0

2 years ago

Which polyhedron has more faces than a hexahedron, but fewer faces than an dodecahedron?

timurjin [86]

The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

Octahedron (8) is a <span>polyhedron has more faces than a hexahedron, but fewer faces than an dodecahedron.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0

2 years ago

Read 2 more answers

What is the area of a rhombus with dimensions of 22 inches and 10 inches?

docker41 [41]

The answer to the problem is 220

3 0

3 years ago

Read 2 more answers

What are the solutions of |3x + 2| >9?

frosja888 [35]

Answer

-11/3>x>7/3

Step-by-step explanation:

|3*7/3+2|=9

|7+2|=9

|9|=9

9=9

therefore, x must be > 7/3

|3*-11/3+2|=9

|-11+2|=9

|-9|=9

9=9

therefore, x must be < -11/3

8 0

3 years ago