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3 years ago

Help i keep getting it wrong :(

Mathematics

2 answers:

liubo4ka [24]3 years ago

8 0

Answer: 65.4

V = pi r^2 h/3

V = pi (2.5^2) (10/3)

V = pi (6.25) (3.33)

V = 65.4

Stolb23 [73]3 years ago

5 0

Answer:

$v = \pi {r}^{2} \frac{h}{3} = {2.5}^{2} \times 3.14 \times \frac{10}{3} = 65.416$

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Item 6 Your city is represented in a coordinate plane where each unit represents 1 kilometer. The library is at (−3, −3), the po

Snezhnost [94]

We know, shortest distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is :

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So, distance between house and library is :

$d_1=\sqrt{(-5-(-3))^2+(2-(-3))^2}\\\\d_1=5.39\ km$

Distance between library and post office :

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\D=\sqrt{(-3-2)^2+(-3-2)^2}\\\\D=7.07\ km$

Distance between post office and house :

$D=\sqrt{(2-(-5)^2)+(2-2)^2}\\\\D=7\ km$

Therefore, minimum distance that you can ride your bike is (5.39+7.07+7) km = 19.46 km.

Hence, this is the required solution.

8 0

3 years ago

Solve for x in the picture below.

netineya [11]

Ok so there's 5 sides

let's find interior angle sum

formula is S=180(n-2)

n in this case is 5 since there are 5 sides

S=180(5-2)
S=180(3)
S=540

so now add the 5 angle lengths up to 540

5x+2+10x-3+7x-11+13x-31+8x-19=540
43x+-62=540
+62 +62
43x=602
divide both sides by 43
x=14!!!!!

6 0

2 years ago

If a group of distinct objects can be arranged in 120 different ways, how many objects are there?

vovikov84 [41]

Answer:

B.4

Step-by-step explanation:

hope this helps:)

3 0

3 years ago

Suppose you flip a fair coin N times. Let random variable h be the number of heads that occur. Use the normal approximation to e

Mariana [72]

Answer:

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

Step-by-step explanation:

Since the coin is fair, then the probability that a filp is heads is 1/2. Given N tries, the amount of heads can be approximated with a Normal distribution with mean μ = N *1/2 = N/2 and standard deviation σ = √(N*1/2 * 1/2) = √N/ 2

The density function of that random variable is given by de following formula

$f_X(k) = \frac{1}{\sqrt{2\pi} * \sigma} e^{\frac{-(k-\mu)^2}{2\sigma^2} } = \frac{2}{\sqrt{2\pi N}} e^{\frac{-2(k-N/2)^2}{N} }$

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

4 0

3 years ago

Help fast pls i’ll give a lot of points

photoshop1234 [79]

Answer:

I cant see this

Step-by-step explanation

3 0

3 years ago