Highest common factor of 28,40,12 and 24

Mathematics

2 answers:

Viefleur [7K]3 years ago

5 0

Answer:

Step-by-step explanation:

28÷4=7

40÷4=10

12÷4=3

24÷4=6

7, 10, 3 and 6 cannot be divided by any same number.

nadezda [96]3 years ago

3 0

Answer:

Step-by-step explanation:

We want to find the highest common factor

Breaking them into factors

28 = 4*7 = 2*2*7

40 = 4*10 = 2*2*2*5

12 = 4*3 = 2*2*3

24 = 3*8 = 3*2*2*2

The factor that appears in all is 2*2

2*2 =4

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Harrizon [31]

Answer:

$\mathrm{No\: solutions}$

Step-by-step explanation:

Since Connor has worked 12 hours walking dogs, he's earned $12\cdot 8 = \$96$ from walking dogs. He still needs to earn $\$160-\$96=\$64$ . As stated in the problem, he makes $12 an hour landscaping, therefore the minimum number of whole hours he must work to fulfill his requirements is $\lceil{ \frac{64}{12} \rceil = 6\: \mathrm{hours}$ . However, the problem states he can only work a maximum of 15 hours. He would have to work $12+6=18$ to fulfill his requirements and therefore he will not be able to meet his requirements with the restrictions given.