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3 years ago

Highest common factor of 28,40,12 and 24

Mathematics

2 answers:

Viefleur [7K]3 years ago

5 0

Answer:

Step-by-step explanation:

28÷4=7

40÷4=10

12÷4=3

24÷4=6

7, 10, 3 and 6 cannot be divided by any same number.

nadezda [96]3 years ago

3 0

Answer:

Step-by-step explanation:

We want to find the highest common factor

Breaking them into factors

28 = 4*7 = 2*2*7

40 = 4*10 = 2*2*2*5

12 = 4*3 = 2*2*3

24 = 3*8 = 3*2*2*2

The factor that appears in all is 2*2

2*2 =4

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3 years ago

Read 2 more answers

The diagonals of rectangle ABCD intersect at point E. If AE = 2x + 5, and BD = 5x + 2, what is AC?

Mkey [24]

C. 42 units

Step-by-step explanation:

I have attached a diagram to help you understand this problem. By looking at the diagram you can see that AE is half of BD, and that BD will be equal to AC. So we need to figure out the length of line BD to get AC.

To do this, you will multiply the length of AE by 2 and set it equal to BD.

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