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sveta [45]
3 years ago
8

If a 11 inch wheel cost $21.35 what is the cost per square inch

Mathematics
1 answer:
Natali [406]3 years ago
8 0

Answer:

$1.94 per square inch

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
likoan [24]

Answer:

A)  3%

B)  Product A

Step-by-step explanation:

<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

<u>Part A</u>

<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

  • a = 10,100
  • b = 1.01
  • n = t - 1 (as the initial value is for t = 1 not t = 0)

\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

4 0
2 years ago
The scale on a map is 1 cm : 6 km. If two cities are 13 cm apart on the map, what is the actual distance between the cities?
AnnZ [28]

Answer:

78 km!

Step-by-step explanation:

13 cm * 6 km per cm = 78 km in actual distance

4 0
2 years ago
a car traveled 36 miles in 45 minutes. the car traveled at a constant speed. it the car continues to travel at this rate which e
Alchen [17]
Y = 48 becuase you travelled the amount of minuets 45 x
8 0
3 years ago
What are the coordinates of the point on the directed line segment from (-6, -3) to
melamori03 [73]

Given:

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.

To find:

The coordinates of that point.

Solution:

Section formula: If point divides a line segment in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5. Using section formula, we get

Point=\left(\dfrac{6(5)+5(-6)}{6+5},\dfrac{6(8)+5(-3)}{6+5}\right)

Point=\left(\dfrac{30-30}{11},\dfrac{48-15}{11}\right)

Point=\left(\dfrac{0}{11},\dfrac{33}{11}\right)

Point=\left(0,3\right)

Therefore, the coordinates of the required point are (0,3).

3 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
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