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Lostsunrise [7]
3 years ago
6

Instructions: Determine whether the

Mathematics
1 answer:
algol133 years ago
4 0

Answer:

No, the above polynomials aren't similar as they don't have a constant scale factor

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Answer to the question
Zepler [3.9K]

Answer:

x = 23

Step-by-step explanation:

AE = EC

so, 5x + 3 = 118

5x + 3 = 118

Bring +3 to the other side so -3

5x = 118 - 3

5x = 115

Bring 5 to the other side so:

x = 115 ÷ 5

x = 65

7 0
3 years ago
What is the exact value of sin(157.5°)?
goldfiish [28.3K]

Answer:

\frac{\sqrt{2 - \sqrt{2} } }{2}

Step-by-step explanation:

sin ^{2}  (157.5°)  =  1/2(1 - cos(2*157.5))

==>  1/2(1 - cos(315))

==>  1/2(\sqrt{2}   /2)

==>  (2 - \sqrt{2} ) / 4

sin(157.5°)  is in quadrant ll , meaning sin(157.5°) is greater than 0 , so we take positive square root of sin(157.5°)

sin(157.5) = \frac{\sqrt{2 - \sqrt{2} } }{2}

3 0
4 years ago
What is the common denominater of 1/5 and 7/10
maks197457 [2]

Answer:

10 010 10 10 10 10 101 01 mo1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is 445612356978 / 238875760=
stellarik [79]
445612356978 / 238875760= 

1865.45657449
6 0
3 years ago
Write the point -slope form of the equation of each line given the slope and y-intercept. Slope=(2/3), y-intercept =0
MakcuM [25]

Answer:

\large\boxed{y-0=\dfrac{2}{3}(x-0)\to y=\dfrac{2}{3}x}

Step-by-step explanation:

The point-slope form of ane equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point on a line</em>

<em />

We have:

m=\dfrac{2}{3}

y-intercept is for x = 0.

Therefore, if y-intercept = 0, then we have the point (0, 0).

y-intercept=0\to(0,\ 0)

Substitute:

y-0=\dfrac{2}{3}(x-0)\to y=\dfrac{2}{3}x

6 0
4 years ago
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