A silicon wafer is textured to minimize light reflection. This results in a surface made up of square pyramids. Each triangular face of one of the pyramids has a base of 5 micrometers and a height of 5.6 micrometers. Find the surface area of the pyramid, including the base.
1 answer:
Answer:
86.33 square micrometers
Step-by-step explanation:
A silicon wafer is textured to minimize light reflection. This results in a surface made up of square pyramids. Each triangular face of one of the pyramids has a base of 5 micrometers and a height of 5.6 micrometers. Find the surface area of the pyramid, including the base.
The formula for the Surface Ares mma is given as :
A=a² + 2a √a²/4+ h²
a = base edge = 5 micro meters
h = height = 5.6 micro meters
=5²+2× 5 × √5²/4+ 5.6²
= 86.32699 square micrometers
≈ 86.33 square micrometers
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Step-by-step explanation:
Emily = x
Peter = Emily - 4 = x - 4
Joshua = 2(Peter) = 2(x - 4)
Total = 40 = Emily + Peter + Joshua = (x) + (x - 4) + 2(x - 4)
40 = 2x - 4 + 2x -8
40 = 4x - 4 - 8
40 = 4x - 12
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x = 13
Emily = 13
Peter = 13 - 4 = 9
Joshua = 2(13 - 4) = 2(9) = 18
13 + 9 +18 = 40
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