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KengaRu [80]
3 years ago
8

A silicon wafer is textured to minimize light reflection. This results in a surface made up of square pyramids. Each triangular

face of one of the pyramids has a base of 5 micrometers and a height of 5.6 micrometers. Find the surface area of the pyramid, including the base.
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0

Answer:

86.33 square micrometers

Step-by-step explanation:

A silicon wafer is textured to minimize light reflection. This results in a surface made up of square pyramids. Each triangular face of one of the pyramids has a base of 5 micrometers and a height of 5.6 micrometers. Find the surface area of the pyramid, including the base.

The formula for the Surface Ares mma is given as :

A=a² + 2a √a²/4+ h²

a = base edge = 5 micro meters

h = height = 5.6 micro meters

=5²+2× 5 × √5²/4+ 5.6²

= 86.32699 square micrometers

≈ 86.33 square micrometers

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3 years ago
The cost of a taxi ride is equal to $3.50 plus $0.25 for each mile. If a ride costs a total of $6.75 how long was the ride?
jeka57 [31]

Answer:

13 miles

Step-by-step explanation:

Write and solve an equation involving this information, using x as the distance traveled, in miles:

Cost(x) = $6.75 = $3.50 + ($0.25/mile)x

First, subtract $3.50 from both sides, obtaining:  $3.25 = ($.25/mile)x.

Next, divide both sides by $0.25/mile:

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3 years ago
Select the correct answer
lora16 [44]

Answer:

Data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20}

Step-by-step explanation:

The question is:

Which data set has the greatest spread for the middle 50% of its data

We have given the data sets:

{18,13,22, 17, 21, 24}

{17,19,22,26,17,14}

{13,17,12,21, 18,20}

{18,21,16,22,24,15}

To find the greatest spread for the middle we need to find the IQR for all the data sets and check which one is highest.

So,

For the first set: 22-17 = 5

For the second: 22-17 = 5

For the third set = 20-13 = 7

For the fourth set = 22-16 = 6

Since data set 3 has the highest IQR, so the correct option is {13,17,12,21, 18,20}  ....

8 0
3 years ago
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Answer:

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Step-by-step explanation:

It is given that we should buy at least 5 newspapers for every 3 television ads.

So, after purchasing 3 television ads, we can buy any number of television ads but the number should be greater than 5.

Since, the maximum is 62, we can buy 59 newspaper ads. (Note that we have already bought 3 television ads).

For every 3 television ads, we should buy 5 newspaper ads. So,

For the purchase of 3 television ads, we should buy the minimum of 5 newspaper ads.

For the purchase of 2(3) television ads, we should buy the minimum of 2(5) newspaper ads.

For the purchase of 3(3) television ads, we should buy the minimum of 3(5) newspaper ads.

...

...

For the purchase of 7(3) = 21 television ads, we should buy the minimum of 7(5) = 35 newspaper ads.

So, totally 21+35 = 56 ads.

For the remaining 6 ads, if we buy 3 television ads, we should buy 5 newspaper ads.

So, we can buy 2 television ads and 4 newspaper ads.

Hence, we can buy the maximum of 21+2 = 23 television ads.

7 0
3 years ago
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Answer:

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Step-by-step explanation:

See the step-by-step solution in the picture attached below.

I hope this answer will help you. Have a nice day !

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