Answer:
0.5 represent the original 100% but we want to obtain a 75% aditional so we can find for the value x if interest and we got:
So we need to sell the fries ar 0.875$ if we want to obtain a 75% of margin
Step-by-step explanation:
For this case we know that the french fries cost $0.50 and we want to have a margin of 75% on the fries. So we can use the following proportional rule:
0.5 represent the original 100% but we want to obtain a 75% aditional so we can find for the value x if interest and we got:
So we need to sell the fries ar 0.875$ if we want to obtain a 75% of margin
Answer:
c =38
Step-by-step explanation:
<71 has an arc of 2 * 71 =142
The arc 104+ c
142 = 104+c
142-104 =c
c =38
Answer:
The probability that the first die will have ""a natural number greater than 1 which can only be divisible by 1 and itself = 0.5
Step-by-step explanation:
A die has 6 faces with the following sample spaces 1, 2, 3, 4, 5 and 6
Then, a natural number greater than 1 which can only be divisible by 1 and itself is the definition of a prime number.
The prime numbers in the sample space are 2, 3 and 5
So, probability of getting a prime number in the sample space, P(prime numbers) = n(prime numbers)/[n(sample space)] = 3/6 = 1/2 = 0.5
Let b be black bean
Let r be red bean
b=4r...(1)
b+4r=75....(2)
(1)-> (2) b+4r=75
4r+4r=75
8r/8 =75/8
r=9.375.....(3)
(3)-> (1) b=4r
b=4(9.375)
b=37.5
Answer:
Se requiere 12 cajas con 4 manzanas y 3 duraznos cada una.
Step-by-step explanation:
Se requiere el menor número posible de manzanas y duraznos para obtener el mayor número de cajas. Puesto que no se considera cortar fruta alguna en porciones y sabiendo que hay más manzanas que duraznos, se determina la razón mínima de manzanas por duraznos:
Se requiere 4 manzanas por cada 3 duraznos. Entonces, cada caja debe contener 3 duraznos y 4 manzanas. El número máximo de cajas es:
Se requiere 12 cajas con 4 manzanas y 3 duraznos cada una.
