The product of two even numbers is even.
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Things to think about:
Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?
Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?
Why did I specifically say that m and k were integers?
The product of two odd numbers is an odd number.
Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.
The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as
2 ( 2mk + m + k ) + 1 which is an odd number.
Answer:
we determine that none of the ordered pair is a solution of 
as none of the ordered pairs satisfy the equation.
Step-by-step explanation:
Considering the equation
- Putting (-5,2) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (0,-5) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (5,1) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (7,5) in the equation
∵ L.H.S ≠ R.H.S
FALSE
From the above calculations, we determine that none of the ordered pair is a solution of as none of the ordered pairs satisfy the equation.
Answer:
slope is 4
Step-by-step explanation:
Answer:
X= (7;-2)
Step-by-step explanation:
X2+5X-14
(X-7)(X+2)
X= 7;-2
Okay you have 2 sum unknow lets call them X+Y
so X+Y=33, 4X=108
Get X by it self then plug it in 4X=108
X=-Y+33
4(-y+33)= 108
-4y+132=108 Then subtract the 132
-4y=-24 Y=6 then to find X subtract 33-6=27
Y=6 X=27 if you check it works out
