I hope this helps you
✔cos^2A+sin^2A=1
✔1-cos^2A=sin^2A
✔cos2A=cos^2A-sin^2A
✔sin2A=2.sinA.cosA
secA=1/cosA
tgA=sinA/cosA
sin^2A/1/cos^2A-sin^2A/cos^2A
sin^2A.cos^2A/cos2A
2.sin^2A.cos^2A/cos2A
sin2A.2.sin2A/cos2A
tg2A.2.sin2A
The correct answer would be B
Why this would be correct is that time fever dtipsbit is always going so that consists of the elevator still moving
Answer:
(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.
Step-by-step explanation:
To find the quotient of the division:
![-3\dfrac13 \div \dfrac49](https://tex.z-dn.net/?f=-3%5Cdfrac13%20%5Cdiv%20%5Cdfrac49)
Step 1: ![\text{Write}$ $ -3\dfrac13$ as $ -\dfrac{10}{3}](https://tex.z-dn.net/?f=%5Ctext%7BWrite%7D%24%20%24%20-3%5Cdfrac13%24%20as%20%24%20-%5Cdfrac%7B10%7D%7B3%7D)
![-3\dfrac13 \div \dfrac49 = -\dfrac{10}{3} \div \dfrac49](https://tex.z-dn.net/?f=-3%5Cdfrac13%20%5Cdiv%20%5Cdfrac49%20%3D%20%20-%5Cdfrac%7B10%7D%7B3%7D%20%5Cdiv%20%5Cdfrac49)
Step 2: Find the reciprocal of ![\dfrac94](https://tex.z-dn.net/?f=%5Cdfrac94)
![-\dfrac{10}{3} \times \dfrac94\\=-7\dfrac12](https://tex.z-dn.net/?f=-%5Cdfrac%7B10%7D%7B3%7D%20%5Ctimes%20%5Cdfrac94%5C%5C%3D-7%5Cdfrac12)
<span> we know the length of the cable is 9m.
That means the magnitude of </span><span><span>r<span><span><span>AB</span></span><span></span></span></span>=9</span><span>m.
The unit vector, denoted u, is each of </span><span>r<span><span><span>AB</span></span><span></span></span></span><span> divided by the magnitude.
</span>u=<span>(<span><span>x/9</span><span></span></span>i−<span>y/9<span></span></span>j−<span>z/9<span></span></span>k<span>)
</span></span><span>We can also figure out the unit vector of F.
</span>u=(350i - 250j - 450k)/√(350² +(-250)² +(-450)²)
u=0.562i−0.401j−0.723<span>k
</span>
<span>Force F is directed from point A to B, then both unit vectors must be equal.
Therefore
</span>(x/9i−y/9j−z/9k)=0.562i−0.401j−0.723k
<span>We can now solve for each term
x/9=0.562----- > x=5.058 m
-y/9=-0.401--------- > y=3.609 m
-z/9=-0.723------- > z=6.507 m
The answer is
the coordinates of point a
(5.058,3.609,6.507)
</span>
Let's call the width: w
the lenght is then 3w+4 ("4 more than 3 times the width")
and the parameter would be 2(w+3w+4), that is 2*(4w+4), that is 8w+8.
this is also equal to 18.4:
8w+8=18.4
8w=10.4
w=1.3
this is the width, and the lenght is:
4+3*1,3=4+3.9=7.9
and the area is their product:
1.3*7.9=10.27