The beaker of acetic acid will cool more quickly.
The specific heat capacity of acetic acid is about half that of water.
Thus, it takes twice as much heat gain (or loss) in acetic acid to cause a given change in temperature.
If everything else is constant and heat is being lost at the same rate, the temperature of the acetic acid should drop twice as fast as that of water.
Answer:
Group 2A (or IIA) of the periodic table are the alkaline earth metals: beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). They are harder and less reactive than the alkali metals of Group 1A.
Explanation:
B. White Dwarf.
<h3>Explanation</h3>
The star would eventually run out of hydrogen fuel in the core. The core would shrink and heats up. As the temperature in the core increases, some of the helium in the core will undergo the triple-alpha process to produce elements such as Be, C, and O. The triple-alpha process will heat the outer layers of the star and blow them away from the core. This process will take a long time. Meanwhile, a planetary nebula will form.
As the outer layers of gas leave the core and cool down, they become no longer visible. The only thing left is the core of the star. Consider the Chandrasekhar Limit:
Chandrasekhar Limit: 
.
A star with core mass smaller than the Chandrasekhar Limit will not overcome electron degeneracy and end up as a white dwarf. Most of the outer layer of the star in question here will be blown away already. The core mass of this star will be only a fraction of its 
, which is much smaller than the Chandrasekhar Limit.
As the star completes the triple alpha process, its core continues to get smaller. Eventually, atoms will get so close that electrons from two nearby atoms will almost run into each other. By Pauli Exclusion Principle, that's not going to happen. Electron degeneracy will exert a strong outward force on the core. It would balance the inward gravitational pull and prevent the star from collapsing any further. The star will not go any smaller. Still, it will gain in temperature and glow on the blue end of the spectrum. It will end up as a white dwarf.
Answer:
C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)
2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)
Explanation:
Butane gas (C₄H₁₀) burns in oxygen gas to produce carbon dioxide gas and water vapor. The unbalanced equation is:
C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)
First, we will balance carbon and hydrogen which are in just one compound on each side.
C₄H₁₀(g) + O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)
Finally, we will balance the oxygen atoms.
C₄H₁₀(g) + 6.5 O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)
In order to have integers, we will multiply everý compound by 2.
2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)
The enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
Potassium trioxonitrate (V) KNO₃(s) is a strong oxidizing solid substance that when dissolved in water changes to aqueous solution.
In its aqueous solution state, the randomness of molecules increases as a result of that the entropy will also increase leading to the positive state of the entropy.
Similarly, provided that the solution becomes quite cold to the touch, the enthalpy is also in it positive state.
Therefore, we can conclude that the enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.
Learn more about Potassium trioxonitrate (V) KNO₃(s) here:
brainly.com/question/25303112
