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MrRa [10]
3 years ago
14

How many grams of water are produced if you combust 1.28 g of C6H14? The balanced equation is:

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
7 0

Answer:

Explanation:

according to the balance chemical equation

2 moles of c6h14 give us 14 moles of H2O

now mass(in gram) of 2 moles of C6H14 is

moles=mass/molar mass

mass=molar mass*moles

molar mass of C6H14 is 86 therefore

mass=86*2=172

now mass of 14 moles of water is

mass=molar mass*moles

molar mass of water is 18

mass=18*14=252

from the above calculations we conclude that  

172 grams of C6H14 produce 252 grams of water

so 1.28 grams of C6H14 produce =252*1.28/172=1.87 grams of water

result is that 1.28 grams of C6H14 produced 1.87 grams of water

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arlik [135]

<u>0.549 mol</u> of citric acid are in 1.50 qt of lemon juice (d = 1.09 g/mL) that is 6.82% citric acid.

<h3>What is citric acid?</h3>

Citric acid is an organic compound with a chemical formula ofHOC(CO_2H)(CH_2CO_2H)_2 . It is a weak organic acid that is colourless. Citrus fruits naturally produce it. It is a biochemical intermediary in the citric acid cycle, which is a process that all aerobic organisms go through during metabolism.

Every year, more than two million tonnes of citric acid are produced. It is frequently employed as a chelating agent, an acidifier, and a flavouring

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8 0
1 year ago
When ethane (
LuckyWell [14K]

Answer:

9 Moles

Explanation:

C2H6 has 6 Hydrogens and Water Has 2 Hydrogens

so it takes 1 mole ethane to produce 3 moles water

1 Mole Ethane ----> 3 Moles Water so 3 ----> 9 moles

7 0
3 years ago
How does a phenol red-containing solution look if co2 level is low?
vampirchik [111]

Answer:

The variables to be examined in relation to carbon dioxide use are the amount of light exposure and amount of dissolved CO2. Phenol red is yellow/orange under acidic conditions, that is when the pH of the solution is less than 7 (e.g. pH = 6). This occurs when the concentration of CO2 is high.

Explanation:

is this correct

4 0
3 years ago
PLEASE HELP I HAVE THIS TEST TOMORROW AM GIVING MORE POINTS THAN I SHOULD
zavuch27 [327]

Answer:

41.11 g of Ca(OH)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + H2O —> Ca(OH)2

Next, we shall determine the masses of CaO and H2O that reacted and the mass of Ca(OH)2 produced from the balanced equation. This can be obtained as follow:

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

Molar mass of H2O = (2x1) + 16

= 2 + 16

= 18 g/mol

Mass of H2O from the balanced equation = 1 × 18 = 18 g

Molar mass of Ca(OH)2 = 40 + 2(16 + 1)

= 40 + 2(17)

= 40 + 34

= 74 g/mol

Mass of Ca(OH)2 from the balanced equation = 1 × 74 = 74 g

From the balanced equation above,

56 g of CaO reacted with 18 g of H2O to produce 74 g of Ca(OH)2.

Finally, we obtained the mass of calcium hydroxide, Ca(OH)2 produced from the reaction of 33 g of CaO and 10 g of H2O. This can be obtained as follow:

From the question given above, we were told that when 33 g of CaO and 10 g of H2O reacted, 2 g of CaO were remaining. This implies that H2O is the limiting reactant and CaO is the excess reactant.

Thus, we shall use the limiting reactant to determine the mass of calcium hydroxide, Ca(OH)2 produced because it will give the maximum yield as all of it is consumed in the reaction.

The limiting reactant is H2O and the mass of calcium hydroxide, Ca(OH)2 produced can be obtained as follow:

From the balanced equation above,

18 g of H2O reacted to produce 74 g of Ca(OH)2.

Therefore, 10 g of H2O will react to produce = (10 × 74)/18 = 41.11 g of Ca(OH)2.

Therefore, 41.11 g of Ca(OH)2 were obtained from the reaction.

3 0
3 years ago
63 C = _____ 63 K 336 K 210 K 163 K
swat32
T K = ºC + 273

T = 63 + 273

T = 336 K

hope this helps!

4 0
3 years ago
Read 2 more answers
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