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Stella [2.4K]
3 years ago
7

What would happen to a diver who does no exhale while surfacing from a 30 m dive?

Chemistry
1 answer:
sertanlavr [38]3 years ago
6 0
Their lungs would try to expand to about 4 timed the normal volume which would force air into the various body tissues. this can cause a lung expansion injury and it could case air embolism. Air embolism is when air bubbles get trapped in blood vessels. This can lead to a blockage which will could be fatal.
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Pleeeeasee someone who’s good at chemistry?! 10 grade
VashaNatasha [74]

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Explanation:

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Need help with this
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3 years ago
Aspirin (C9H8O4) is an acid which can be titrated with a base to determine purity. If an aspirin tablet weighing 0.615 g is titr
Iteru [2.4K]

Answer:

67.4 % of C₉H₈O₄

Explanation:

To make titrations problems we know, that in the endpoint:

mmoles of acid = mmoles of base

mmoles = M . volume so:

mmoles of acid = 20.52 mL . 0.1121 M

mmoles of acid = mg of acid / PM (mg /mmoles)

Let's determine the PM of aspirin:

12.017 g/m . 9 + 1.00078 g/m . 8 + 15.9994 g/m . 4 = 180.1568 mg/mmol

mass (mg) = (20.52 mL . 0.1121 M) . 180.1568 mg/mmol

mass (mg) = 414.4 mg

We convert the mass to g → 414.4 mg . 1g / 1000mg = 0.4144 g

We determine the % → (0.4144 g / 0.615 g) . 100 = 67.4 %

6 0
3 years ago
How many moles of NaCl are created as a result of decomposing 12 grams of NaClO3? (molar mass of Na=23, Cl=35, O=16)
Harman [31]

Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} NaClO_3=\frac{12g}{106.5g/mol}=0.113moles

The balanced chemical equation for decomposition of NaClO_3 is:

2NaClO_3\rightarrow 2NaCl+3O_2  

According to stoichiometry :

2 moles of NaClO_3 give = 2 moles of NaCl

Thus 0.113 moles of NaClO_3 give =\frac{2}{2}\times 0.113=0.113moles  of NaCl

Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

8 0
3 years ago
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