B is the answer
I double checked hope it helps
3.18 grams of product (Cu I) - 2.54 grams of Cu (reactant) = .64 grams of Sulfur, by law of conservation of mass.
Answer:
<em>The mole ratio of PbO2 to H2O is 1 : 2.</em>
Explanation:
The balanced reaction equation is:
Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O
On the reactant side, we have 1 mole of Pb, 1 mole of PbO2, 2 moles of H2SO4.
On the product side, we have 2 moles of PbSO4 and 2 moles of H2O.
This means that for ever 1 mole of PbO2 consumed, 2 moles of water is formed as product.
Hence, the mole ratio of PbO2 to H2O is 1 : 2.
Answer:
a)
[SO2]: The concentration increases
[O2]: The concentration increases.
[SO3]: The concentration decreases.
b)
[SO2]: The concentration decreases.
[O2]: The concentration decreases.
[SO3]: The concentration increases.
c)
[SO2]:There is no change.
[O2]: There is no change.
[SO3]: There is no change
Explanation:
For an exothermic reaction, increase in temperature decreases the concentration of products and increases the concentration of reactants since increase in temperature shifts the equilibrium position to the left hand side.
Increase in pressure and decrease in volume will shift the equilibrium position towards the right hand side which means more SO3 in the system.
Catalyst increases the rate of forward and reverse reaction simultaneously hence at equilibrium, the concentration of reactants and products remain unchanged.
