49.491 millimeters of acid is present
<em><u>Solution:</u></em>
Given that, chemist is using 351 milliliters of a solution of acid and water
14.1% of the solution is acid
To find: Milliliters of acid present
From given statement,
Solution of acid and water = 351 ml
14.1% of the solution is acid, which means that 14.1 % of 351 ml is acid
Therefore,
Milliliters of acid present = 14.1 % of 351 ml
Here "of" means multiplication
Therefore,
Thus 49.491 millimeters of acid is present
Answer:
interval level of measurement
Step-by-step explanation:
Interval level of measurement is numeric and allows for mathematical operations like mean. It is quantitative and in fixed units, i.e changes in values are as a result of a phenomenon. It does not have a zero point i.e a value of zero does not mean what you are measuring is absent, for example a temperature of 0°C do not mean there is no heat applied. It specifies the distance between intervals.
Answer:
2775.9
Step-by-step explanation:
options are
A) 578
B) 2775.9
C) 134.591
D) 31.757
Value of digit 5 in 4.59 is 0.5 as is is at tenth place after decimal
0.5 = 5/10
ten times of this value = 5/10*10 = 5
Thus, 5 is the value, and hence the number which we require should be at unit place of the required number.
In the given question
A) 578
here 5 is at hundredth place
other way to represent is is 500+70+8
B) 2775.9
here 5 is unit place and is correct option
it can be represented as
2000+ 700+ 70+ 7 + 9/10
c)C) 134.591
here 5 is tenth place after decimal
it can be represented as
100+ 30+ 5 + 5/10+9/100 + 1/1000
d)31.757
here 5 is hundredth place after decimal
it can be represented as
30+ 1 + 7/10+5/100 + 7/1000\
Hence, 2775.9 is correct choice.
Answer:
<u>11</u><u>+</u><u>2</u><u>3</u><u>i</u>
<u>simplified</u><u> </u><u>using</u><u> </u><u>Foil</u>
Answer: Direct proportion because as the time goes up the distance goes up
