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3 years ago

PQRS is a quadrilateral.

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

7 0

Answer:

y = 95° (being corresponding angle)

it is very easy.

you can also do

djyliett [7]3 years ago

3 0

Answer:

The value of y is 110 degrees

Step-by-step explanation:

-we know that the Angle sum property of a quadrilateral is 360 degrees.

- so we can find the 4th angle

- and find y through the linear pair method.

The fourth angle=70 degrees

And y=180-70=110(Linear pair)

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Answer:

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3 years ago

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Find the equation of a line that passes through (-5,4) and us parallel to y=-6/7x+3

irina [24]

Given:

The given equation of line is

$y=-\dfrac{6}{7}x+3$

To find:

The equation of line that passes through (-5,4) and is parallel to the given line.

Solution:

Slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

We have,

$y=-\dfrac{6}{7}x+3$ ...(ii)

On comparing (i) and (ii), we get

$m=-\dfrac{6}{7}$

Slope of given line is $m=-\dfrac{6}{7}$ .

Slope of parallel lines are same. So, slope of parallel line is $m=-\dfrac{6}{7}$ .

The required line passes through (-5,4) with slope $m=-\dfrac{6}{7}$ . So, the equation of line is

$y-y_1=m(x-x_1)$

$y-4=-\dfrac{6}{7}(x-(-5))$

$y-4=-\dfrac{6}{7}(x+5)$

$y-4=-\dfrac{6}{7}x-\dfrac{30}{7}$

Adding 4 on both sides, we get

$y=-\dfrac{6}{7}x-\dfrac{30}{7}+4$

$y=-\dfrac{6}{7}x+\dfrac{-30+28}{7}$

$y=-\dfrac{6}{7}x-\dfrac{2}{7}$

Therefore, the correct option is a.

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3 years ago

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Answer:

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