4% of ___ days is 56days

1 answer:

3 0

We calculate this like this:

$\frac{4}{100} *x=56
$

where x is the desired number. 4 percent of x is 56
$\frac{4} *x=56*100
$

here i multiplied both sides by 100

$x= \frac{56*100}{4}
$

I divided both sides by 4, then on the left hand side only x is left!

$x= \frac{56*25}{4}
$

$x= 1400
$

The answer is 1400

You might be interested in

-3(3x+15)-(10+x)=35 What is the answer to this ques5

Misha Larkins [42]

Solve for x:
-3 (3 x + 15) - (x + 10) = 35

-3 (3 x + 15) = -9 x - 45:
-9 x - 45 - (x + 10) = 35

-(x + 10) = -x - 10:
-9 x + -x - 10 - 45 = 35

Grouping like terms, -x - 9 x - 45 - 10 = (-9 x - x) + (-45 - 10):
(-9 x - x) + (-45 - 10) = 35

-9 x - x = -10 x:
-10 x + (-45 - 10) = 35

-45 - 10 = -55:
-55 - 10 x = 35

Add 55 to both sides:
(55 - 55) - 10 x = 55 + 35

55 - 55 = 0:
-10 x = 35 + 55

35 + 55 = 90:
-10 x = 90

Divide both sides of -10 x = 90 by -10:
(-10 x)/(-10) = 90/(-10)

(-10)/(-10) = 1:
x = 90/(-10)

The gcd of 90 and -10 is 10, so 90/(-10) = (10×9)/(10 (-1)) = 10/10×9/(-1) = 9/(-1):
x = 9/(-1)

Multiply numerator and denominator of 9/(-1) by -1:

Answer: x = -9

7 0

4 years ago

Read 2 more answers

Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the coefficient 'k' in the factored form? 6x3 + 4x2 − 6x − 4 = 2(x

anastassius [24]

$6x^3+4x^2-6x-4 =\\ 2(3x^3+2x^2-3x-2) =\\ 2(x^2(3x+2)-1(3x+2))=\\ 2(x^2-1)(3x+2)=2(x+1)(x-1)(3x+2).$

So k=1.

5 0

3 years ago

A number is ten less than seven times the number. What is the number?

Grace [21]

X+10=7x
10=6x
10/6=x
1 4/6 = x
1 2/3 =x

Hope this helps :)

6 0

3 years ago

Solve using the quadratic formula 2x^2+x+67=0

telo118 [61]

Answer:

$\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Multiple Roots
Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}$
[√Radical] Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}$
[√Radical] Simplify: $\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$