Question

Write the equation of the circle with center (3, 2) and (−6, −4) a point on the circle.

Answer 1

Answer:

D

Step-by-step explanation:

Took the test

Answer 2

Answer:

D. $(x-3)^2 + (y-2)^2 = 117$

Step-by-step explanation:

To write the equation of a circle, use the formula $(x-h)^2+(y-k)^2 = r^2$ where the center of the circle is (h, k).

This means the equation is $(x-3)^2 + (y-2)^2 = r^2$.

Find the radius r by finding the distance between (3,2) and (-6,-4) using the distance formula.

$d = \sqrt{(-6-3)^2 + (-4-2)^2} =\sqrt{(-9)^2 + (-6)^2} =\sqrt{81+36} =\sqrt{117}$

Since the radius is √117 and therefore $r^2 = 117$.

The equation is $(x-3)^2 + (y-2)^2 = 117$.