For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:
Answer:
Step-by-step explanation:
To answer this specific problem, the measure of ∡DEF
is 64. I am hoping that this answer has satisfied your query and it will
be able to help you in your endeavor, and if you would like, feel free to ask
another question.
I'm pretty sure you would need to multiply 2/5 by 40.
So, if you multiply 2/5 by 40, you need to turn 40 into a fraction with 1 being the denominator.
2/5 x 40/1 = 80/5
Since the product is an improper fraction, you would simplify it to a whole number.
80/5 = 16.
He can expect to hit it 16 times to get a hole in one.
I hope I am right and have a great day.
Gives an output of 1 I think
