Answer:
0.010
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score = 63 inches
μ is the population mean = 70 inches
σ is the population standard deviation = 3 inches
For x shorter than 63 inches = x < 63
Z score = x - μ/σ
= 63 - 70/3
= -2.33333
Probability value from Z-Table:
P(x<63) = 0.0098153
Approximately to the nearest thousandth = 0.010
Therefore, the probability that a randomly selected student will be shorter than 63 inches tall, to the nearest thousandth is 0.010.
The last one represents a function ..
Answer:
We conclude that garbage collector's average picking is more than four tons of garbage per day.
Step-by-step explanation:
We are given the following information n the question:
First, we design the null and the alternate hypothesis
Significance level = 5% = 0.05
P-value = 0.04
- The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.
- P values evaluate how well the sample data support that the null hypothesis is true.
- P-value is a measure or indicator that helps us to know that whether the sample belongs to the population or not.
- Null hypothesis states that the sample belongs to the population.
- A high p-values states that the null hypothesis is true ad the sample belongs to the population.ll.
- A low p-value suggests that sample provides enough evidence that you the null hypothesis is not true and the sample does not belong to the population.
- We compare p-value to significance level to obtain our result.
Here,
p-value = 0.04 < Significance level = 0.05
Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject it. That is there were enough evidence to support the fact that sample does not belong to the population and we conclude that garbage collector's average picking is more than four tons of garbage per day.
Step-by-step explanation:
The only way the answer could be E is if the x² term under the radical is supposed to be t².
f(x) = ∫₄²ˣ √(t² − t) dt
f'(x) = √((2x)² − 2x) (2)
f'(x) = 2√(4x² − 2x)
f'(2) = 2√(4(2)² − 2(2))
f'(2) = 2√12