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2 years ago

Choose the situation in which using exact numbers is the MOST appropriate.

Mathematics

2 answers:

valentinak56 [21]2 years ago

8 0

Answer:

Step-by-step explanation:

QveST [7]2 years ago

3 0

Answer:

A, you need to pay with exact change

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125+25x = 50 I need a answer quickly

antoniya [11.8K]

Answer:

-3

Step-by-step explanation:

Subtract 25x 125=-25x+50

Subtract 50 125-50= -25x

Simplify 75= -25x

Divided 75 by negatrive 25

8 0

2 years ago

What divided by 14 will equal 29

Paladinen [302]

X/14=29
x=14*29
x=406

Hope this helps :)

3 0

2 years ago

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A restaurant receives a shipment of

natka813 [3]

Subtract the amount used from the total packets:

5000 - 1824 = 3176 left after the first week.

3176 - 2352 = 824 total packets left.

7 0

2 years ago

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

7 0

2 years ago

Make a list of all 3 digit numbers using the digit 5, 2, and 6

HACTEHA [7]

Answer:

SOLUTION #1

If the digits are allowed to repeat, the answer is 27. (There are three ways to fill digit 1, three ways to fill digit 2, and three ways to fill digit 3. Therefore, there are 3 x 3 x 3 = 27 possibilities.)

SOLUTION #2

If the digits are NOT allowed to repeat, the answer is 6. (There are three ways to fill digit 1, only two ways to fill digit 2, and only one way to fill digit 3. Therefore, there are 3 x 2 x 1 = 6 possibilities.)

Step-by-step explanation:

Hope this <em><u>Helped!</u></em> :D

5 0

2 years ago

Read 2 more answers