Part C
2 answers:
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Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z = ~ N(0,1)
where, = population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P( <
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
Answer:
1. ∠ABD = 20°.
2. Arc AB = 140°.
3. Arc AD = 40°.
Step-by-step explanation:
Given information: ∠ADB = 70°. BD is diameter.
According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.
By Central angle theorem,
Using angle sum of property in triangle ADB we get,
.
Draw a line segment AO.
In triangle AOD, AO=OD, so
Using angle sum property in triangle AOD,
Therefore length of arc AD is 40°.
The angle AOD and AOB are supplementary angles.
Therefore length of arc AB is 140°.
