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lisov135 [29]
2 years ago
11

Part C

Mathematics
2 answers:
Marina CMI [18]2 years ago
7 0

Answer:

Jacob:

Alive 69-70

alive 79-80

alive 62-63

alive 73-74

alive 78-Died 79

Carol:

alive 88-89

alive 67-68

alive 99-100

alive 73-74

alive 94- Died 95

Step-by-step explanation: edmentum

Katyanochek1 [597]2 years ago
5 0
Dog u needa offer more points for this
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Simplify<br> X2-49<br> Over <br> X2+9x+14
Stels [109]

Answer:

(x-7)/(x+2)

Step-by-step explanation:

(x-7)(x+7)/(x+7)(x+2)

(x-7)/(x+2)

7 0
3 years ago
Is 1:2:3 equivalent to 2:4:6​
Finger [1]

Answer:

Yes it is.

Step-by-step explanation:

Just multiply everything by 2.

5 0
3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
What is the number between 40 and 45
LiRa [457]
43 is between the 40 and 45
7 0
3 years ago
Read 2 more answers
Mistaken giving brainliest!!! Tho
vitfil [10]

Answer:

its C

Step-by-step explanation:

;););)

8 0
3 years ago
Read 2 more answers
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