The answer is 1.52 to your question.
Ending Amount = Beginning Amount / 2^n
where 'n' = # of half lives
n = 20,000 / 1,600 = 12.5 half-lives
Ending Amount = 1 kg / 2^12.5
Ending Amount = 1 kg /
<span>
<span>
<span>
5,792.6
</span></span></span>Ending Amount =
<span>
<span>
<span>
0.00017263 kilograms = </span></span></span><span>0.17263 grams
</span>
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
brainly.com/question/11732255
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Answer:
3x^3+3x^2+5x-8
Step-by-step explanation:
Answer:
84 <em>m</em>^2
Step-by-step explanation:
A = <em>bh</em>
multiply the parallelogram's height, 7, by it's base, 12. (7 × 12 = 84)
