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Sindrei [870]
2 years ago
15

Please help!!! I will mark someone brainliest!

Mathematics
1 answer:
valina [46]2 years ago
3 0

Answer:

a = 8, b = \frac{3}{2}

Step-by-step explanation:

Given the exponential function

f(x) = ab^{x}

To find a and b use the given coordinate points on the graph

Using (0, 8 ), then

8 = ab^{0} [ b^{0} = 1 ] , then

a = 8

f(x) = 8b^{x}

Using (2, 18 ) , then

18 = 8b² ( divide both sides by 8 )

\frac{18}{8} = b² , that is

b² = \frac{9}{4} ( take the square root of both sides )

b = \sqrt{\frac{9}{4} } = \frac{3}{2}

Thus

f(x) = 8(\frac{3}{2}) ^{x}

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Step-by-step explanation:

3 0
2 years ago
Domain and, range in interval notation
Bas_tet [7]

Domain: [-4,4]  (left-to-right or x-values used)

Range: [-4,4] (down-to-up or y-values used)

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4 0
2 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
Larry read a 400400400-page book. He read at a rate of 101010 pages per day for ddd days. Write an equation that could be used t
ira [324]

Answer:

From Larry's rate, the equation can be given as D = T/101010

Step-by-step explanation:

Larry's book has 400400400 pages

His reading rate is 101010 pages per day

Let D = Number of days to read the book

To get the number of days it takes fro Larry to read this book, we say

Total pages = Reading rate (pages/day) x Number of days

Let Total pages = T

and Reading rate = R

Hence;

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From Larry's rate, the equation can be given as D = T/101010.

From the question,

ddd = 400400400 (pages) / 101010 (pages/day) = 3963.9 days

Hence, it takes Larry approximately 3964 days to read the book.

7 0
3 years ago
A guy-wire is attached to a pole for support. If the angle of elevation to the pole is 67° and the wire is attached to the groun
vovangra [49]
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4 0
3 years ago
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