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3 years ago

HELPPPPPPP PLSSSSSSSS

Mathematics

1 answer:

liberstina [14]3 years ago

8 0

Answer:

D'(5,2)

E'(13,-5)

F'(15,3)

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Circle M has a radius of length 5 inches. A tangent is drawn from exterior point Q to point N on circle M as shown. If QN= 11 in

Marina CMI [18]

Answer:

look at the box did you see it

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3 years ago

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Can someone plz help me with this

Ronch [10]

The line is right in the middle of 100 and 110 degrees so the answer should be 105 degrees. This tool is called a protractor. :)

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3 years ago

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Which phrase best describes the translation from the graph y=(x-5)^2+7 to the graph of y=(x+1)^2-2

Helga [31]

Start from the parent function $f(x)=x^2$

In the first case, you are computing

$f(x-5)+7$

In the second case, you are computing

$f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)$ , you translate the function horizontally, $k$ units left if $k>0$ and $k$ units right if $k$ .

On the other hand, when you transform $f(x) \to f(x)+k$ , you translate the function vertically, $k$ units up if $k>0$ and $k$ units down if $k$ .

So, the first function is the "original" parabola $f(x)=x^2$ , translated $5$ units right and $7$ units up. Likewise, the second function is the "original" parabola $f(x)=x^2$ , translated $1$ units left and $2$ units down.

So, the transformation from $(x-5)^2+7$ to $(x+1)^2-2$ is: go $6$ units to the left and $2$ units down

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3 years ago

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ronaldo delivers the papers at the rate of 6 papers in 24 minutes. how much longer would it take him to deliver 56 papers than 4

UkoKoshka [18]

We are given

Ronaldo delivers the papers at the rate of 6 papers in 24 minutes

so, number of papers =6 in time =24 minutes

so, firstly we can find rate

rate = ( number of papers)/( time taken)

$r=\frac{6}{24} =\frac{1}{4}$

now, we can find times

Time for 56 papers:

we are given

number of papers =56

rate is

$r=\frac{1}{4}$

now, we can find time

$t_1=\frac{56}{r}$

$t_1=\frac{56}{\frac{1}{4}}$

$t_1=224min$

Time for 41 papers:

we are given

number of papers =41

rate is

$r=\frac{1}{4}$

now, we can find time

$t_2=\frac{41}{r}$

$t_2=\frac{41}{\frac{1}{4}}$

$t_2=164min$

now, we can find time difference

$t=t_1-t_2$

so, we can plug values

$t=224-164$

$t=60 min$ ..............Answer

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3 years ago

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Stu hiked a trail at an average rate of 3 miles per hour. He ran back on the same trail at an average rate of 5 miles per hour.

Andrews [41]

3t = 5(3-t)
3t = 15 - 5t
3t + 5t = 15
8t = 15
t = 15/8
t = 1 7/8

7/8 * 60 mins = 52.50 minutes

t = 1 hour and 52.5 minutes

It took Stu 1 hour and 52.5 minutes to hike the trail one way.

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4 years ago

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