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ladessa [460]
2 years ago
7

How many solutions does the equation -3(2x+5)=-15 have?

Mathematics
1 answer:
Mamont248 [21]2 years ago
4 0

Answer:

Step-by-step explanation:

-3(2x+5)=-15

-6x-15= -15

-6x=0

No solutions

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Gavin and his three friends want to share 1/3of cake equally. Gavin says that each friend will get 1/9 of the cake. Use the drop
Alexxandr [17]

Answer: Incorrect

Step-by-step explanation:

Given

Gavin and his three friends wants to share \frac{1}{3} of cake equally.

So, there are 4 members to distribute the cake

Each member will get

\Rightarrow \dfrac{\dfrac{1}{3}}{4}\\\\\Rightarrow \dfrac{1}{3\times 4}=\dfrac{1}{12}

So, each member get one-twelvefth of the given cake.

Hence, Gavin is  incorrect.

6 0
3 years ago
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Given f(x) = 2x^2 -3x and g(x) = x+4
Alenkasestr [34]

Answer:

2x³ + 5x² - 12x

Step-by-step explanation:

The correct answer doesn't seem to be listed...

(fg)(x) = (2x² - 3x)(x + 4)

Which equals...

2x²(x) + 2x²(4) + (-3x)(x) + (-3x)(4)

Which simplifies to...

2x³ + 8x² - 3x² - 12x

     2x³ + 5x² - 12x

8 0
3 years ago
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Solve question please​
JulijaS [17]

Answer:

289

Step-by-step explanation:

17^{2}

17x17

= 289

Hope this helps

3 0
2 years ago
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Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
Please help, I don’t understand this at all..
kkurt [141]
Answer: 120

Explanation






6 0
3 years ago
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