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ladessa [460]
2 years ago
7

How many solutions does the equation -3(2x+5)=-15 have?

Mathematics
1 answer:
Mamont248 [21]2 years ago
4 0

Answer:

Step-by-step explanation:

-3(2x+5)=-15

-6x-15= -15

-6x=0

No solutions

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R/3+2=21 solve for r
olchik [2.2K]

Answer:

r=63

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    r/3-(21)=0             r

Simplify   —

           3

r    

 — -  21  = 0

 3     2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

         21     21 • 3

   21 =  ——  =  ——————

         1        3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

7 0
3 years ago
find three consecutive even integers so that the twice the sum of the second and third is twelve less than six times the first
zysi [14]

n, n + 2, n + 4 - three consecutive even integers

the twice the sum of the second and third: 2[(n + 2) + (n + 4)]

twelve less than six times the first: 6n - 12

The equation:

2[(n + 2) + (n + 4)] = 6n - 12

2(n + 2 + n + 4) = 6n - 12

2(2n + 6) = 6n - 12       <em>use distributive property</em>

(2)(2n) + (2)(6) = 6n - 12

4n + 12 = 6n - 12       <em>subtract 12 from both sides</em>

4n = 6n - 24       <em>subtract 6n from both sides</em>

-2n = -24        <em>divide both sides by (-2)</em>

n = 12

n + 2 = 12 + 2 = 14

n + 4 = 12 + 4 = 16

<h3>Answer: 12, 14, 16</h3>
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Step-by-step explanation:

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Rami picked 16 oranges

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