Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
0.23
Step-by-step explanation:
Using either long division or a calculator, divide 23 by 100; you will get the result 0.23.
The reciprocal of 7/2 is 2/7
Answer:A is correctly scientifically notated
B is incorrect
C is correctly notated
D is correct. 10 to the zero power simply means “1”
Step-by-step explanation:
Answer:
J
Step-by-step explanation:
<h2>multiply 185 by 12=2220</h2><h3>you now know you need to find blank=2220</h3><h3 />
- F = 12(100)+12(13)
- G = 12(1)+12(8)+12(5)
- H= 12(18)+12(5)
- J= 12(100)+12(80)+12(5)
12*10=120
12*100=1200
12*12=144
12*13=156
12*18=216
12*5=60
12*8=96
f=1200+156=1356
g=12+96+60=168
h=216+60=276
j=1200+960+60=2220
