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3 years ago

1/2n+3<5 what is the answer to this problem

Mathematics

1 answer:

postnew [5]3 years ago

6 0

Algebra

The answer to this problem is to simply simplify it.

$\frac{1}{2} n + 3 < 5$

Subtract three from both sides.

$\frac{1}{2} n < 2$

Multiply both sides by two.

$n < 4$

Meaning, n is anything below four.

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A carpenter charges $720 for 18 hours of work. She charges the same amount of money for each hour of work.

Rainbow [258]

Answer:

Step-by-step explanation:

To start off, you know 18 hours= 720

So you could automatically get rid of B and D since 19 and 17 are not 18.

After that, you have it down to A and C. The way you would find how much she charges for one hour is dividing 720 by 18. When you do that it means you are divding 720$ into 18 different groups each group representing an hour. When you divide 720 by 18 you should get 40. So every hour she makes 40 dollars. 40x 2 hours is 80. I hope I helped you!

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3 years ago

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In a seminar of 1200 people, 65 percent were women, How many men were in the seminar?

Nookie1986 [14]

Answer:

420

Step-by-step explanation:

If there were 1200 people, and 65 percent were women, that means the rest of the crowd are men, which is 35 percent. By multiplying 35 percent by the overall population, 1200, (1200*35/100), you'll get 420 men.

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3 years ago

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Simplify: 2x²(4x³-3x²+6x)

eimsori [14]

Answer
8x^3 - 6x^4 + 12x^3

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The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of

ycow [4]

The length of the longer base is 41 ft.

Explanation

Lets assume, length of one base is $x$ ft.

As, another base is 19 less than five times the length of this base, so the length of another base $= (5x- 19) ft.$

The trapezoid has a height of 18 ft and area of 477 ft²

Formula for Area of trapezoid, $A=\frac{1}{2} (a+b)*h$ , where $a, b$ = Two bases of trapezoid and $h$ = height of the trapezoid.

Given in the question: $A= 477$ and $h= 18$

We have also two bases as: $a= x$ and $b= 5x-19$

So, according to the above formula...

$A= \frac{1}{2}(a+b)h\\\\ 477=\frac{1}{2}(x+5x-19)*18\\\\ 477=9(6x-19)\\\\477= 54x-171\\\\477+171=54x\\\\648=54x\\\\x=\frac{648}{54} = 12$

So, length of one base is $12 ft$ and another base $=(5*12-19)ft =(60-19)ft = 41 ft$

That means, the length of the longer base is 41 ft.

8 0

3 years ago

A box is 12 centimeters wide ,12 centimeters long, and 15 centimeters tall. What is the total surface area of 4 such boxes?

Grace [21]

First you want to find the surface area of one box
SA=2(l*w)+2(h*l)+2(h*w)
SA=2(12*12)+2(15*12)+2(15*12)
SA=2(144)+2(180)+2(180)
SA=288+360+360
SA=1008 cm² is for one box
Multiply by 4 to get for 4 boxes
4*1008=4032 cm²

4 0

3 years ago