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Kobotan [32]
3 years ago
6

Adult tickets to the fall play cost $8 and student tickets cost $4. The drama class sold 20 more adult tickets than student tick

ets
to the fall play. If the class collected $840 from ticket sales, how many adult tickets were sold?
The drama class sold
adult tickets
Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0

Answer:

A= 80

Step-by-step explanation:

I'm not good at explaining my work. I sometimes can look at the problem and find the answer in 2 seconds.

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In a football stadium, 43% of the crowd cheering for Team A, and 52% of the crowd is female. 19% of the crowd is cheering for Te
musickatia [10]
P(TeamA) = 0,43
P(Female) = 0,52
P(TeamA and Female) = 0,19
P(TeamA or Female) = ?

P(TeamA or Female) = P(TeamA) + P(Female) - P(TeamA and Female) <=>

P(TeamA or Female) = 0,43 + 0,52 - 0,19 <=>

P(TeamA or Female) = 0,76 or 76%
4 0
3 years ago
The diagram shows a logo​
Charra [1.4K]

Answer/Step-by-step explanation:

✔️Find EC using Cosine Rule:

EC² = DC² + DE² - 2*DC*DE*cos(D)

EC² = 27² + 14² - 2*27*14*cos(32)

EC² = 925 - 756*cos(32)

EC² = 283.875639

EC = √283.875639

EC = 16.85 cm

✔️Find the area of ∆DCE:

Area = ½*14*27*sin(32)

Area of ∆DCE = 100.15 cm²

✔️Since ∆DCE and ∆ABE are congruent, therefore,

Area of ∆ABE = 100.15 cm²

✔️Find the area of the sector:

Area of sector = 105/360*π*16.85²

Area = 260.16 cm² (nearest tenth)

✔️Therefore,

Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)

5 0
3 years ago
Find the area of the trapezoid.<br> Answer options: 8sqrt2, 4sqrt3, 12.0, 16sqrt2
Elis [28]

Answer:

=  8sqrt2

Step-by-step explanation:

Area of a trapezium is given by the formula;

1/2(a+b)h ;

Where a and b are the parallel sides and h is the perpendicular height.

a = 3 cm, b= 5 cm

To get; h, we use the Pythagoras theorem;

h² = 3² - 1²

   h² = 8

h = √8

  = √4√2

 = 2√2

Thus;

Area = 1/2(3 +5) 2√2

         = 1/2 ×8 × 2√2

       <u>  = 8√2 cm² or  8sqrt2 cm²</u>

8 0
3 years ago
What is 1.21 divided by .11
wariber [46]
Your answer is 0.0909090909 if I'm not mistaken.
4 0
3 years ago
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Write each equation in logarithmic form.<br><br><br> 5^3 = 125
mojhsa [17]

Answer:

log5(125)=3 The 5 should be smaller and a little lower.

Step-by-step explanation:

8 0
3 years ago
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