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Nataliya [291]
3 years ago
14

Find the area of the trapezoid. Answer options: 8sqrt2, 4sqrt3, 12.0, 16sqrt2

Mathematics
1 answer:
Elis [28]3 years ago
8 0

Answer:

=  8sqrt2

Step-by-step explanation:

Area of a trapezium is given by the formula;

1/2(a+b)h ;

Where a and b are the parallel sides and h is the perpendicular height.

a = 3 cm, b= 5 cm

To get; h, we use the Pythagoras theorem;

h² = 3² - 1²

   h² = 8

h = √8

  = √4√2

 = 2√2

Thus;

Area = 1/2(3 +5) 2√2

         = 1/2 ×8 × 2√2

       <u>  = 8√2 cm² or  8sqrt2 cm²</u>

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Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

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Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

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