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castortr0y [4]
3 years ago
10

Wats 3/4 x12 plus the work and how to solve it

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0

Answer:

9

Step-by-step explanation:

You divide 3 by 4 first and you'll get the anser 0.75, then multiply it by 12.

leonid [27]3 years ago
7 0

Answer:

solution

3/4×12

=3×3

=9

I hope this will help you more

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Is the answer 20?
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3 years ago
I literally have a test tomorrow and dont know what to do please help
Fittoniya [83]
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3 0
3 years ago
Read 2 more answers
3/2=4/3x+2/3 What does X equal?
Anna71 [15]

Answer:

x = 30/48 or x = 0.625

Step-by-step explanation:

3/2 = 4/3x + 2/3

Convert to common denominator

9/6 = 8/6x + 4/6

subtract 4/6 from both sides

9/6 - 4/6 = 8/6x + 4/6 - 4/6

5/6 = 8/6x

Divide by 8/6

5/6 x 6/8 = x

30/48 = x

x = 30/48

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5 0
3 years ago
Lin rode her bike 2 miles in 8 minutes. She rode at a constant speed. How
hodyreva [135]

Answer: 4

Step-by-step explanation:

For this question, we have to divide the number 8 by 2.

8 ÷ 2 = 4

Now, we have to take the quotient, 4, and multiply it by 1.

1 x 4 = 4

The answer is 4.

6 0
3 years ago
A go-cart racetrack has 100-meter straightaways and semicircular ends with diameters of 40 meters. Calculate the average speed i
emmainna [20.7K]

Answer:

Average speed of go cart is 217.07 meters per minute.

Step-by-step explanation:

We are given the following in the question:

Length of straightway racetrack = 100 m

Diameter of  semicircular end = 40 m

Radius =

r = \dfrac{d}{2} = \dfrac{40}{2} = 20\text{ m}

Perimeter of racetrack =

Perimeter of semicircle + 2(Length of straightway) + Perimeter of semicircle

=\pi r + 2(100) + \pi r\\=2\pi r + 2(200)\\=(2\times 3.14\times 20) + 200\\=325.6\text{ m}

Speed =

s = \dfrac{\text{Distance}}{\text{Time}}\\\\s = \dfrac{4\times \text{Perimeter of track}}{6}\\\\s = \dfrac{4\times 325.6}{6}\\\\s = 217.06\text{ meter per minute}

Thus, average speed of go cart is 217.07 meters per minute.

4 0
3 years ago
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