Answer:
y=6
Step-by-step explanation:
The equation of the line with slope 2 is y=2x+b, b is a constant which should be determined. The line passes via through points (1, 2) and (3,y)
(1, 2): 2=2+b --> b=0
So, the equation of the line is y=2x. Now, when x=3, y=6. So the line y=2x passes through points (1, 2) and (3, 6). (3,y)=(3, 6).
Answer:
![\frac{\sqrt[4]{30} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B30%7D%20%7D%7B3%7D)
Step-by-step explanation:
Step-by-step explanation:
Given equation is
2y = 3x + 10
3x - 2y + 10 = 0 .....i)
Any line parallel to line I) is
3x - 2y + k = 0 ......ii)
As the line two passes through the point ( 2 , - 5 ) Now substituting the values
3 * 2 - 2 * ( - 5) + k = 0
6 + 10 + k = 0
16 + k = 0
k = - 16
Now putting the value of k in equation two
3x - 2y + 16 = 0 is the required equation.
Hope it will help :)❤
7 × 100
+ 0 × 10
+ 6 × 1
0 x 0.1 1/10
+ 3 × 0.01 1/100
+ 9 × 0.001 1/1000
